### Homework Help - Series Program

Write a function that returns the value of the following series.
f(n, y) = (1/y)( 2 + 1/3 + 4 + 1/5 + 6 + 1/7 + ... + x )
where the values n is the number of terms and y is a multiplication coefficient. Both n and y are supplied by the user and passed to the function. The main function should continue to query the user for values of n and y and print the result until the y is entered as a zero.

This is what i currently have but I am very confused and not too sure where to go from here. Thanks

[code]
#include <iostream>
#include <string>
#include <cmath>

using namespace std;

float function(int,double);

int n;
double x;

int main(void)
{

cout<<"Enter the value for x:";
cin>>x;
if (x !=0)
{
cout<<"Enter the number of terms : ";
cin>>n;
cout<<"\nSUM = "<<function(n,x)<<endl;
}
else
return 0;
}
float function(int n, double x)
{
double func = 0.0;
float sum = 0.0;

for(int i=1;i<=n;i=i+1)
{
for(int j=0;j<=n;j=j+1)
{
func = (1/x)*(2*i+(1/(j+2)));
sum+=func;
}
}

return func;
}
There is something called recursion in which a function calls itself from within its own definition block.
Think about what the pattern is in the series and come up with a way to apply that with recursion. Remember to come up with a way to break out of the recursion or you'll end up with an infinite loop that will eventually crash the program.

Example of recursion:
 ``1234`` ``````double SimpleSummation(double start, double rate){ if(rate > 0.0001) return start*rate + SimpleSummation(start,rate-0.15); else return 0; }``````

Hint: You might need pow().

Edit:
Just noticed that you also need the main function to continue asking the user for new n and y values. You can wrap your input and function call within a loop.
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