A question about pointers?

[Edward01]

What is the difference between these two codes?

	int *ptr = new int;
	int x(7);
	cout<<"x:"<<x<<endl;//output 7;
	*ptr = x;
	cout<<"&ptr: "<<&ptr<<endl;

and the second one:

	int *ptr = new int;
	int x(7);
	cout<<"x:"<<x<<endl;//output 7;
	*ptr = x;

	cout<<"ptr: "<<ptr<<endl;

which one prints me the adress of ptr? and what the other one prints?

thank you!

[coder777]

the first one prints the address of the pointer.
the second prints the value of the pointer (somehow the pointer itself)

[vlad from moscow]

That it would be clear consider the following simple example

int x = 10;
int *p = new int( 20 );

std:;cout << x << std::endl; // prints what is stored in x that is 10
std:;cout << &x << std::endl; // prints the address of x

std:;cout << p << std::endl; // prints what is stored in p 
                             // that is the address of the allocated memory
std::cout << &p << std::endl; // prints the address of p itself 

[Edward01]

thanks