String help

[jwkNwA7f]

How can I check how many characters are there in a string using an array.

I got this far, but I am not sure what to put for the condition.

for (int i = 0;  ; i++)
{
   ...
}

Thank you!

[Hertz]

okay,
How many characters are in a certain string?

or

How many characters are in the whole array?

[metulburr]

if your for loop is not in a function that takes the array as an argument, you can use
sizeof(a)/sizeof(a[0])

[Xiledcore]

Are you talking about counting letters in a string that's in an array?

Or are you talking about counting characters in a string?

If so, here's an example code:

#include <iostream>
#include <string>

int main()
{
    int iLength;
    std::string something("Hello");
    iLength = something.length();
    
    std::cout << "There are: " << iLength << " Characters in " << something << std::endl;
    return 0;
}

[jwkNwA7f]

How many characters are in a string.

Maybe I misunderstood the meaning of an array.
I thought this was considered working using an array:

string word;
string char2;
// Some code for user input
char1 = word[1];

[andywestken]

I am not sure what to put for the condition.

C strings are null terminated.

So you need to loop for the null char '\0'

Andy

[jwkNwA7f]

Maybe I was using the wrong approach.

I think using word.length(); will solve my problem.

Thank you!

[Hertz]

string word;
string char2;
// Some code for user input
char1 = word[1];

First let me show you how to make an array. Basically an array is a group of datatypes put together. So editing your last code.

string word[]; // Makes an array of strings.
string char2;
//some code for user input
char1 = word[1];

I usually make a constant for the number of elements I want in the array. So to answer your first question.

#include<iostream>
#include<string>

using namespace std;

int  main()
{

        const int arrayLength = 5; //size of the array.
        string words[arrayLength] = {"Bill Gates", "Steve Jobs", "Bjarne Stroustrup" , "cppprogrammer297","Hertz"}; //an array of strings with arrayLength number of elemtents.

        for (int i = 0; i < arrayLength  ; i++)
        {

                cout << words[i] << " has " << words[i].size() << " characters in it \n"; //loops through the array and gets the size of each string in the current index(i).

        }

        cout << endl;

}

[jwkNwA7f]

Thank you, Hertz!

That is what I was looking for.

[Dy7SLyTq]

you know if you use vectors it allows for more size control, memory management, and you can just use vector::size();

[jwkNwA7f]

Okay, I will try that to, DTSCode.

Thank you!