how to cin without repeating the statement.

[fujin009]

note: i can only use <iostream>

what i need to do is to input a value and if it's false then i will need to input another value again in the same statement without repeating it..so basically my previous "cin" value is gone in the output..

what I only know

Pincode: 123456 (if wrong the Pincode still remains)
 Pincode: (Pincode repeats itself so i can input again which is not what i need to do)

output should be like this..

Pincode: 123456 (if its wrong i will need to input something in the Pincode again but the statement
 Pincode should not be repeated but i will still be able to input beside it)

arrghh its hard to explain it like this lol

if the value is wrong

Pincode:123

this should happen

Pincode:

not repeating it with the word "Pincode"

and there still this..

Welcome Guest!
Pincode:

thats the output if the pincode is not yet entered..so when i input the correct pincode it will become like this

Welcome President!
Pincode:123456

again not repeating the statement

the codes that i was just able to make where a simple cout and cin nothing else..please do tell me nicely to explain it again if you can't understand :)

[Chriscpp]

Post your code.

[chipp]

you mean, password field should't display the asterisks?

[fujin009]

#include <iostream>
using namespace std;
int main()
{
   
    cout<<" Welcome Guest!"; //have to change "Guest" to "President" if pin is correct  without repeating the statement                                  
    cout<<endl;
 
   string pin;
  for (;pin!="123456";)//i just use for loop more often 
  {
      cout<<"Pincode: ";
      getline(cin,pin);

//what happens here is, if i input the wrong pin it repeats the

//cout<<"Pincode: ";  
//getline(cin,pin);

/*but what I need is to repeat cin without repeating the cout<<"Pincode"; which means 
when i retype the pin value i will still be typing beside the FIRST "Pincode:" the first value
that i inputted will be replaced and that is where i type again...its like starting all over again/*
  }
return 0;
} */

[Chriscpp]

#include <iostream>
#include <stdlib.h>
using namespace std;
int main()
{
   string pin;
  for (;pin!="123456";)//i just use for loop more often
  {
      cout<<" Welcome Guest!"<<endl;
      cout<<"Pincode: ";
      getline(cin,pin);
      system("CLS");
  }
  cout<<" Welcome President!"<<endl;
return 0;
}

[fujin009]

sorry ive seen the output wrong..problem solved with system("CLS");

int priority;
        for(;priority!=1||priority!=2||priority!=3||priority!=4||priority!=5;)
        {
            cout<<"Enter Priority Number: ";
            cin>>priority;
        }

am i doing this right?cuz even if i enter 1,2,3,4 or 5 the loop still continues

int priority;
        for(;priority!=1;)
        {
            cout<<"Enter Priority Number: ";
            cin>>priority;
        }

this works though..but i need the 5 numbers..and if i enter a letter it won't proceed to a infinite loop but it will ask to enter priority number again