### Unfixed multiplication table/ Looping Program

Hello, so i did the following code. What I want to do next is to make it unfixed so that I would be able to enter the area I want to start and area I want it to end.
For Example:
Enter the area you want to start : 1
are it will end: 5

So, it will show the multiplication table for 1,2,3,4,5 only up to x10.

 ``123456789101112131415161718`` `````` #include using namespace std; int main () { cout << "\t1\t2\t3\t4\t5\t6\t7\t8\t9\t10" << endl; for (int x=1; x<=10; x++) { cout << x << "|"; for (int y=1; y<=10; y++) { cout << x*y << "\t"; } } system ("pause"); return 0; }``````

Also, I couldn't get "\t1\t2\t3\t4\t5\t6\t7\t8\t9\t10" to fit in the command prompt. Any workarounds?

EDIT:
I got another question.

What I want to do now is the program must return to the main menu unless the exit button is selected.

 ``12345678910111213141516171819202122232425262728293031323334`` ``````int x; int sum=0; int ave=0; cout << " Program Menu " << "\n" << "Please choose one of the following programs" << "\n" << "Option 1: Input a number other than 999." << "\n" << "Option 2: Print //d// five times." << "\n" << "Option 3: Print a multiplication table." << "\n" << "Option 4: PassOrFail grade assessment." << "\n" << "Option 5: Count up to what the user enters" << "\n" << "Option 6: Exit" << endl; cin >> x; switch (x) { case 1: int num; cout << "Please input a number other than 999" << endl; cin >> num; while (num<999) { ave=ave+1; sum=num+sum; cin >> num; } if (num==999) { cout << "The sum is: " << sum << endl; cout << "The average is: " << sum/ave << endl; } break;``````

this is only a part of the program because it's too long but I think this would be enough for you guys to hel pme.
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Probably under your console settings or compiler settings to the amount of characters per line. Or use a few spaces instead of tabs.

You could use basic math and row/column for loops.

 ``123456789101112131415161718192021222324`` ``````for( int row = 0; row < 10; ++row ) { for( int column = 0; column < 10; ++column ) { std::cout << ( column + 1 ) * ( row + 1 ) << '\t'; } std::cout << std::endl; }`````` ```1 2 3 4 5 6 7 8 9 10 2 4 6 8 10 12 14 16 18 20 3 6 9 12 15 18 21 24 27 30 4 8 12 16 20 24 28 32 36 40 5 10 15 20 25 30 35 40 45 50 6 12 18 24 30 36 42 48 54 60 7 14 21 28 35 42 49 56 63 70 8 16 24 32 40 48 56 64 72 80 9 18 27 36 45 54 63 72 81 90 10 20 30 40 50 60 70 80 90 100 Process returned 0 (0x0) execution time : 0.040 s Press any key to continue. ```

*edit if you want an "unfixed" you could just input to two variables and then put those for the maximum row/column

**edit sorry I'm really tired I didn't even look at your code but it looks almost the same as mine if you want an unfixed one try something like this

 ``123456789101112131415161718`` ``````#include int main() { int max_rows = 0 , max_columns = 0; std::cout << "Please enter the maximum rows : " << std::flush; std::cin >> max_rows; std::cout << "Please enter the maximum columns : " << std::flush; std::cin >> max_columns; for( int row = 0; row < max_rows; ++row ) { for( int column = 0; column < max_columns; ++column ) { std::cout << ( column + 1 ) * ( row + 1 ) << '\t'; } std::cout << std::endl; } return( 0 ); }``````
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I think you're ready to make it into a function kind of like this;
 ``1234567891011121314`` ``````void mTable(int start, int end) { for (int x=start; x<=end; x++) { cout << x << " "; } } int main() { mTable(3, 5); int wait; cin>>wait; }``````

I'll leave the actual function programming up to you, but in this case you can type mTable(3, 5); and the numbers 3 through 5 will print to screen, or mTable(1, 10) and 1 through 10 will show up.
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For part two use a do/while loop.

 ``1234567`` ``````int main() { do { //stuff } while( exit_button_not_pressed ); }``````