Unfixed multiplication table/ Looping Program

[sanasuke15]

Hello, so i did the following code. What I want to do next is to make it unfixed so that I would be able to enter the area I want to start and area I want it to end.
For Example:
Enter the area you want to start : 1
are it will end: 5

So, it will show the multiplication table for 1,2,3,4,5 only up to x10.

  #include <iostream>
using namespace std;

int main ()
{
	cout << "\t1\t2\t3\t4\t5\t6\t7\t8\t9\t10" << endl;

	for (int x=1; x<=10; x++)
	{
		cout << x << "|";
		for (int y=1; y<=10; y++)
		{
			cout << x*y << "\t";
		}
	}
	system ("pause");
		return 0;
}

Also, I couldn't get "\t1\t2\t3\t4\t5\t6\t7\t8\t9\t10" to fit in the command prompt. Any workarounds?


EDIT:
I got another question.

What I want to do now is the program must return to the main menu unless the exit button is selected.

int x;
	int sum=0;
	int ave=0;
	cout << "      Program Menu     " << "\n"
		<< "Please choose one of the following programs" << "\n"
		<< "Option 1: Input a number other than 999." << "\n"
		<< "Option 2: Print //d// five times." << "\n"
		<< "Option 3: Print a multiplication table." << "\n"
		<< "Option 4: PassOrFail grade assessment." << "\n"
		<< "Option 5: Count up to what the user enters" << "\n"
		<< "Option 6: Exit" << endl;

	cin >> x;

		switch (x)
	{
		case 1:
			int num;
	
	cout << "Please input a number other than 999" << endl;
	cin >> num;

	while (num<999)
	{
		ave=ave+1;
		sum=num+sum;
		cin >> num;
	}
	if (num==999)
	{
		cout << "The sum is: " << sum << endl;
		cout << "The average is: " << sum/ave << endl;
	}
	break;

this is only a part of the program because it's too long but I think this would be enough for you guys to hel pme.

[giblit]

Probably under your console settings or compiler settings to the amount of characters per line. Or use a few spaces instead of tabs.

You could use basic math and row/column for loops.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24

for( int row = 0; row < 10; ++row ) { for( int column = 0; column < 10; ++column ) { std::cout << ( column + 1 ) * ( row + 1 ) << '\t'; } std::cout << std::endl; }

1 2 3 4 5 6 7 8 9 10 2 4 6 8 10 12 14 16 18 20 3 6 9 12 15 18 21 24 27 30 4 8 12 16 20 24 28 32 36 40 5 10 15 20 25 30 35 40 45 50 6 12 18 24 30 36 42 48 54 60 7 14 21 28 35 42 49 56 63 70 8 16 24 32 40 48 56 64 72 80 9 18 27 36 45 54 63 72 81 90 10 20 30 40 50 60 70 80 90 100 Process returned 0 (0x0) execution time : 0.040 s Press any key to continue.

*edit if you want an "unfixed" you could just input to two variables and then put those for the maximum row/column



**edit sorry I'm really tired I didn't even look at your code but it looks almost the same as mine if you want an unfixed one try something like this

#include <iostream>
int main()
{
    int max_rows = 0 , max_columns = 0;
    std::cout << "Please enter the maximum rows : " << std::flush;
    std::cin >> max_rows;
    std::cout << "Please enter the maximum columns : " << std::flush;
    std::cin >> max_columns;
    for( int row = 0; row < max_rows; ++row )
    {
        for( int column = 0; column < max_columns; ++column )
        {
            std::cout << ( column + 1 ) * ( row + 1 ) << '\t';
        }
        std::cout << std::endl;
    }
    return( 0 );
}

[newbieg]

I think you're ready to make it into a function kind of like this;

void mTable(int start, int end)
{
	for (int x=start; x<=end; x++)
	{
              cout << x << "  ";
        }
}
int main()
{
        mTable(3, 5);
        int wait;
        cin>>wait;

}

I'll leave the actual function programming up to you, but in this case you can type mTable(3, 5); and the numbers 3 through 5 will print to screen, or mTable(1, 10) and 1 through 10 will show up.

[giblit]

For part two use a do/while loop.

int main()
{
    do
    {
        //stuff
    } while( exit_button_not_pressed );
}

*link
http://www.cplusplus.com/doc/tutorial/control/