### 5 to a number

Def: A year is a century year if it is divisible by 100{ex: 100,200}
Def: A year is non- century year if it is not a century year.{ex: 1,2,3}
Def: A year is a leap year if it is a non -century year that is divisible by 4 or a century year divisible by 400 . Nothing else is a leap year.

Write a program that is going to ask the user for the range of years and print out
all leap years in that range 5 to a line ?
I am not able to find how to print 5 numbers to a line
here is my code

//leapyear.cpp
#include <iostream>
using namespace std;

int main ()
{
int n1,n2,counter;
cout << "Please give me a range of year:";
cin >> n1 >> n2;
if(n1<1 || n2<1)
{
cout << "Does not exist";
return 0;
}
for(int c = n1;c<=n2;c++)
{
for(int i = 0 ;i<5;i++)

if((c%100 !=0 && c%4 ==0) || (c%100 == 0 && c%400 == 0))
cout << c << " ";

cout << endl;

}
cout << "These all are leap years in the given range";
cout << endl;
return 0;
}
Last edited on
closed account (3qX21hU5)
Well lets look at how we print 1 number to a lone.

`cout << numberOne;`. That is simple enough. To print 5 numbers per line it is actually just as simple as that.

`cout << numberOne << " " << numberTwo << " " << numberThree << endl;`

Now that only prints 3 numbers then creates a new line but I believe you get the idea. We at in the blank " " to create spaces between each number.
 ``12345678910111213141516171819202122232425262728293031323334`` ``````//leapyear.cpp #include using namespace std; int main () { int n1,n2,counter=0; cout << "Please give me a range of year:"; cin >> n1 >> n2; if(n1<1 || n2<1) { cout << "Does not exist"; return 0; } for(int c = n1;c<=n2;c++) { if((c%100 !=0 && c%4 ==0) || (c%100 == 0 && c%400 == 0)) { if(counter<5) { cout << c << " "; counter++; } else { cout << endl; counter=0; } } } cout << "\nThese all are leap years in the given range"; cout << endl; return 0; }``````
@ahmarajeel

Here is your program, and it checks for valid responses by letting you know what's wrong.
 ``123456789101112131415161718192021222324252627282930313233343536373839404142`` ``````//leapyear.cpp #include using namespace std; int main () { int n1,n2,counter = 0; do { cout << "Please give me a range of years:" << endl; cout << "Starting year : "; cin >> n1; cout << "Ending year : "; cin >> n2; if(n1<0 || n2<0) cout << "Leap years did NOT even exist then. Please try again." << endl; if (n1>n2) { cout << "Ending year MUST be greater than the starting year!!" << endl; n1=0,n2=0; } } while (n1<1||n2<1||n1>n2); for(int year = n1; year<=n2; year++) { if((year%100 !=0 && year%4 ==0) || year%400 == 0) { counter++; cout << year << " "; if (counter == 5) { counter = 0; cout << endl; } } } cout << endl << endl << "These all are leap years in the given range"; cout << endl; return 0; }``````
Thanks you very much Zereo Chriscpp Whitenite.

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