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Help getting dice to roll 10000 times.

layzer (32)
I have to write a program that rolls 2 dice 10000 times in a game of craps and calculate the odds of winning and losing.
I have the program working to 1 roll but honestly i cant figure out how to get it to roll multiple times.

Thanks! Heres the code so far:

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  #include <iostream>	
#include <stdlib.h> 
#include <string> 
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>

using namespace std;

int diceroll(); //funtion reference 

//global variables 
int dice1;
int dice2;
int rollSum;
int sum;
int rollPoint;
double oddslosing;
double odds;
string status;
int w = 0; //wins
int l = 0; //lose
int main()
{
	sum = diceroll();

	switch (sum) //switch for numbers
	{
	case 2:
	case 3:
	case 12:
		status = "lose";
                ++l;
		break;
	case 7:
	case 11:
		status = "win";
                ++w;
		break;
	default:
		status = "point";
		rollPoint = sum;
		break;
	}
	
	
	
	while (status == "point") //point loop
	{

		sum = diceroll();

		
		
		if (sum == rollPoint)
			status = "win";
                       
		else if (sum == 7)
			status = "lose";
		else
			status = "point";
	}
	
	if (status == "win")
		++w;  
	if (status == "lose")
		++l;
odds = ((double)w/(w+l));
oddslosing = ((double)l/(w+l));
cout<< "odds of winning: "<<odds<<endl;
cout<< "odds of losing: "<<oddslosing<<endl;

	return 0;
}
int diceroll() //function for rolldice 
{
	dice1 = (rand() + time(0)) % 6 + 1;
	dice2 = (rand() + time(0)) % 6 + 1;
	rollSum = (dice1 + dice2);
	
	return rollSum;
}
Last edited on
MarketAnarchist (99)
like this perhaps?

i ran it 10 million times for kicks and got
win: .535538
lose: .464462
neat program =)

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#include <iostream>	
#include <stdlib.h> 
#include <string> 
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>

using namespace std;

int diceroll(); //funtion reference 

//global variables 
int dice1;
int dice2;
int rollSum;
int sum;
int rollPoint;
double oddslosing;
double odds;
string status;
int w = 0; //wins
int l = 0; //lose
int main() {
	for (int i=0; i<10000; ++i) {
		sum = diceroll();

		switch (sum) //switch for numbers
		{
		case 2:
		case 3:
		case 12:
			status = "lose";
					++l;
			break;
		case 7:
		case 11:
			status = "win";
					++w;
			break;
		default:
			status = "point";
			rollPoint = sum;
			break;
		}
	
	
	
		while (status == "point") //point loop
		{

			sum = diceroll();

		
		
			if (sum == rollPoint)
				status = "win";
                       
			else if (sum == 7)
				status = "lose";
			else
				status = "point";
		}
	
		if (status == "win")
			++w;  
		if (status == "lose")
			++l;
	}

	odds = ((double)w/(w+l));
	oddslosing = ((double)l/(w+l));
	cout<< "odds of winning: "<<odds<<endl;
	cout<< "odds of losing: "<<oddslosing<<endl;

	cin.ignore();

	return 0;
}

int diceroll() { //function for rolldice 

	dice1 = (rand() + time(0)) % 6 + 1;
	dice2 = (rand() + time(0)) % 6 + 1;
	rollSum = (dice1 + dice2);
	
	return rollSum;
}
Last edited on
layzer (32)
Perfect! Much appreciated!

Thanks! :D
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