### help fixing for loop factorial code

I'm supposed to write a program that uses one variable int n (which should be positive) and use a for or while loop to compute the following sum :
1^3 + 2^3 + 3^3 + ... + n^3

And then I have to store the sum into int sum and print its value but for some reason, when I test out the code, it just freezes after I enter a value for n.

Any help is appreciated. Thanks!

 ``1234567891011121314151617181920212223242526272829`` ``````#include #include #include using namespace std; int main () { char c; int n, i, sum; while (1) { cout << "Press q to quit or anything else to continue "; cin >> c; cin.ignore ( 256, '\n' ); if (c == 'q' or c == 'Q' ) { cout << "\n\nUser quits the program.\n\n"; break; } cout << "Enter a postive integer n = "; cin >> n; sum = 0; for ( i = 1; 1 <= n; i++ ) sum += pow ( i, 3); cout << "The sum is" << setprecision(20) << sum << endl; } return 0; }``````
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Line 23: here you make the sum of the second power of n! Change to 3, I suppose, as you said in your introduction! And you can check your output with the correct value from the formula:
S3 = 13 +23+33+...+n3 = n 2 * (n + 1)2 / 4

Succes!

EDIT: In the meantime when I wrote my reply you have modified that line!:)
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Hello, thank you for your reply. Yes I did modify that line but it still doesn't work!
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Of course it still doesn't work: see line 22: it must be `for(i = 1; i <= n; ++i)`
Try this...:)
Thank you so much! It worked!
Note: sum is an integer because you add only integers (integer powers of integers) so you don't need of `pow` and `math.h`: in this case is simply `sum += i * i * i ;`
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