### Help with "for" loop

Hello,

I am a beginner in C++ and I was looking at a problem involving a "for" loop. I do not understand how to get to the answer. I've successfully compiled the code to verify the answer and it was the same.

If someone could please run me through this. Thank you :)

 ``12345678910`` ``````#include using namespace std; int main(){ int x = 0, i = 1 for (; (i++) <= 5; i+=3) --x; cout << x + i << endl; return 0; }``````

The right answer is 8, but the answer I get is 5.

The way I do it is i starts 1, than gets brought up to 2 since 2 is smaller or equal to 5, it is incremented by 3. This results in 5. Then 5 gets brought up to 6 and the for loop fails. Therefore, the loop ran once and x + i = 6 + (-1) = 5.
Please, put a ; (semicolon) after `i = 1` in the line 5:

`int x = 0, i = 1;`
Last edited on
 The way I do it is i starts 1, than gets brought up to 2 since 2 is smaller or equal to 5, it is incremented by 3.

That would be true if you were using a prefix increment, but you're using a postfix increment.

We begin with i equal to 1. The loop condition compares i before the increment ( 1 <= 5 ) and sets i to i+1 (2). Since the loop condition evaluates to true, the body of the loop is executed making x -1, and then i is increased by 3, making it 5.

We begin this iteration with i equal to 5. The loop condition compares i before the increment (5 <= 5) and sets i to i+1 (6). Since the loop condition evaluates to true, the body of the loop is executed making x -2 and then i is increased by 3 making it 9.

We begin this iteration with i equal to 9. The loop condition compares i before the increment (9 <= 5) and sets i to i+1 (10). Since the loop condition evaluates to false, the body of the loop will not be executed and neither x nor i will change again leaving us with:

i has the value 10 and x has the value -2. -2 + 10 is 8.
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