Get multiple values from cin

[ITR]

Hi! I'm currently in a competition, and I'm practicing by doing some tasks from last year. I found out that they test most programs by giving an input in one single line like this:
"5 3 23"
and that we need to get the three ints 5, 3 and 23 out of it (we get to know how many ints we need, but not the length). Is there an easy way to do this, or do I have to go through the whole string/char array looking for spaces?

Thanks

[The illusionist mirage]

If you input a character or int array as a string using cin, then the delimiter is the first white space it encounters. So, even if you have multiple cin statements, you can input on one line, separating each by a space.

[ITR]

Thanks :3 Do I do this with cin.get? or cin >> intarray?

[ITR]

Didn't work :( I could make it work with cin >> x[0] >> x[1] >> x[2], etc, but that doesn't work when it's variable-sized

[Chervil]

we get to know how many ints we need, but not the length

the length of what exactly? Are you saying that you don't actually know how many ints you need?

[ITR]

I know how many ints I need from a variable, but I don't know how many digits

[Chervil]

Thanks for the clarification ( I think).

However i still don't understand the earlier comment,

Didn't work :( I could make it work with cin >> x[0] >> x[1] >> x[2], etc, but that doesn't work when it's variable-sized

Why or how doesn't it work?

[Edevan]

What about this? 1:

char a[88]="8 3 23";
cout<<a;

What about this? 2:

int b[]={8,3,23};
cout<<b[0]<<" ";
cout<<b[1]<<" ";
cout<<b[2]<<" ";

What about this? 3:

int a[3];
int c;
for(c=0;c<3;c++){
cout<<"Insert a number\n";
cin>>a[c];
}
cout<<a[0]<<" ";
cout<<a[1]<<" ";
cout<<a[2]<<" ";

[ITR]

It's a bit hard to explain, so I'll try again.

The program will be tested by a machine. The machine first gives a value that says how many values it will give next time. Then it gives the all those values in a single line, with space between each value. If I had typed:

string x;
cin >> x;
cout << x;

for the second time it gives a value, and it gives the values 5, 2 and 17, it would come out as "5 2 17".

I want to know if I easily can get those values in an int array.
It cannot give them on multiple lines.

The reason cin >> x[0] >> x[1] >> x[2] won't work, is because then I would need to know how many values it will give, while I'm programming it.

[Chervil]

then how about this:

    int count;
    cin >> count;
    int * array = new int[count];
    for (int i=0; i<count; i++)
        cin >> array[i];

not forgetting to end with delete [] array; when you are finished with the array.

[ITR]

Thanks, that worked, but how? I thought that would make it ask for count lines? With enter between?

[ynooran]

The good things about arrays is that you can use an integer when calling one.

for example:

for(i=0;i<x;i++)//Where x is number of ints
{
     cout<<a[i]<<" ";// where a is name of array.
}

[Chervil]

Thanks, that worked, but how?

the cin>> operator will extract a value delimited by whitespace. In this context, whitespace can be any of space, tab or newline, it makes no difference which is used.