Simple Quiz

[Aksan Akmal]

This time I try to make a quiz with three questions that should be appearing with order. Somehow, I got an "invalid conversion from 'const char' to 'char" error. I wonder why? This is the code.

  #include <iostream>

using namespace std;

int main()
{
    int points = 0;
    char decision, firstquestionlogic, secondquestionlogic, thirdquestionlogic;

    cout << "Answer these five questions below!" << endl;
    cout << "Ready? Y/N " << endl;
    cin >> decision;

    if(decision = "Y")
        {
            cout << "The head of this country is Mr.Abe. Y/N ?" << endl;
            cin >> firstquestionlogic;
            if(firstquestionlogic = "Y")
            {points = points + 100;};

            cout << "Whale is not a mammal. Y/N ?" << endl;
            cin >> secondquestionlogic;
            if(secondquestionlogic = "N")
            {points = points + 100;};

            cout << "The richest person in the world is Steve Jobs. Y/N ?" << endl;
            cin >> thirdquestionlogic;
            if(thirdquestionlogic = "N")
            {points = points + 100;};

        }
    cout << "Your accumlated points is " << points <<endl;

    return 0;
}

[MatthewRock]

const char* is a string(word/sentence)
char is a letter.

And you compare both(and you can't!). Hence, error.

Just change all your conditionals, like in line 14:

if( decision == 'y') // mind the single ' 

And when I wrote it, I noticed that you made second mistake - you assigned "Y" to decision :) Remember,
= is assignment
== is comparision

If you want to be safe from this kind of mistakes, put constants first, like this

if('Y' == decision)

Now, if you made a mistake and instead of == used =, compiler would tell you that you are trying to assign something to constant. Otherwise, if you do assignment in if, you can have a bug that is hard to find.

[Aksan Akmal]

ah, thanks. I should have realized that :(

[iAk3T05o]

This is exactly what i'm doing and thanks to a forum member, i've added more functionality using loops.
You don't have any else if for when the user inputs 'N'.
Have you learnt string, stringstream and getline ?