### Range in switch statement.

//I'm a beginner and I just started doing these test exercises on the forum.
//I'm doing the first one.

http://www.cplusplus.com/forum/articles/12974/

//So, I made this program in which I'm required to have a switch between a range //of numbers. But i can figure out how.

#include <iostream>

using namespace std;

int main()
{
int score;

cin >> score;

switch (score)

{

}

return 0;
}
switch cannot do that. if .. else if .. else if .... else
It's better to use if statements for this because switch cases can only have one value each which means you would have to list all the values in the range if you use a switch.
Ok so I made this program now.

Its giving correct cout for less than 59. But not for other numbers :/

#include <iostream>

using namespace std;

int main()
{
int score;

cin >> score;

if (score <= 59)

else if (score = 60,score <= 69)

else if (score = 70,score <= 79)

else if (score = 80,score <= 89)

else if (score = 90,score <= 100)

return 0;
}
closed account (iAk3T05o)
You use || to represent or not ','
 ``1234567`` ``````else if (score >= 60 || score <= 69) { } //not else if (score >= 60, score <= 69) { }``````

and equality is == not =.
Last edited on
 ``12`` ``````// else if (score = 60,score <= 69) else if( score >= 60 && score <= 69 ) ``````

and likewise for the rest.

With a switch:
 ``123456789101112131415161718192021`` ``````#include int main() { int score; std::cout << "Enter your score (0-100): "; std::cin >> score; char grade = 'F' ; switch( score/10 ) { case 6: grade = 'D' ; break ; case 7: grade = 'C' ; break ; case 8: grade = 'B' ; break ; case 9: case 10: grade = 'A' ; } std::cout << "Your grade is " << grade << '\n' ; }``````
It worked. I used >= and its working just fine now. Thank you so much for your help, everyone.
@JLBorges.

//Just like your I made this one using switch statement. But instead of //telling the grade. It tells the score I put in.

#include <iostream>

using namespace std;

int main()
{
int score;

switch (score/10)

{
case 0: case 1: case 2: case 3: case 4: case 5:grade = 'F';

case 9: case 10:grade = 'A';

}

return 0;
}
Last edited on
Hello talhabhatti5

You can define ranges using 2 points

switch(score)
{
case 0..39: grade = 'D' ; break ;
case 40..59: grade = 'C' ; break ;
case 60..79: grade = 'B' ; break ;
case 80..100: grade = 'A' ; break;
}

In this case your range for the first case is between 0 and 39 both limits included is the same as writing

if (score >= 0) && (score <= 39 )
I made it using the method you told. It not working for me. Why is that?

#include <iostream>

using namespace std;

int main()
{
int score;

switch (score)

{

}

return 0;
}
closed account (iAk3T05o)
Use if and else.

But now I'm trying to make it using a switch. And the method Jecs9 told is not working for me.
@Jecs9 What language is that?
Hello talhabhatti5

Sorry, That way of using the case is for ST, I got confused, in C/C++ if you want to use a kind of range you would need to define every case, for example

switch(score)
{
case 0:
case 1:
case 2:
case 3:
case 4:
// and so on until 59
// then do the same for 60-69

here is an example

{
case 'A' :
cout << "Excellent!" << endl;
break;
case 'B' :
case 'C' :
cout << "Well done" << endl;
break;
case 'D' :
cout << "You passed" << endl;
break;
case 'F' :
cout << "Better try again" << endl;
break;
}

If you don't type a break; after a case and you state another case, both cases will do the same action, as you can see in case 'B' and case 'C', both will output "Well done" because there is no break after case 'B'.

So the best option is using the if statement as some users told you before

the difference between using if and case is that in if each 'if' will be evaluated one by one, in the case, all the cases are evaluated at the same time, I mean, if you are using "if else if" your code first will evaluate if the first condition is true, then the second, third, and so on, if you use case it will execute the corresponding line so the "switch" statement is faster than "if else if"
 the difference between using if and case is that in if each 'if' will be evaluated one by one, in the case, all the cases are evaluated at the same time

Please explain. The switch has a haphazard list of constants that it has to compare the integral value against. These are obviously simpler tests for equality than what the if-clauses might contain. However, the if..else if does not need to evaluate any further than to the first true.

The use of `score/10` maps range 60-69 into value 6 due to the nature of integer division.
 ``123456789101112131415161718192021222324252627282930313233343536373839404142`` ``````// switch const int val = score/10; switch ( val ) { case 5: foo(); break; case 7: bar(); break; default: gaz(); } // equivalent if const int val = score/10; if ( 5 == val ) foo(); else if ( 7 == val ) bar(); else gaz(); // direct if 1 (complicated conditions) if ( 49 < score && score < 60 ) foo(); else if ( 69 < score && score < 80 ) bar(); else gaz(); // direct if 2 (looks worse due to discontinuous "match ranges") if ( score < 50 ) gaz(); else if ( score < 60 ) foo(); else if ( score < 70 ) gaz(); else if ( score < 80 ) bar(); else gaz(); // direct if 2 with more clear scopes if ( score < 50 ) gaz(); else { if ( score < 60 ) foo(); else { if ( score < 70 ) gaz(); else { if ( score < 80 ) bar(); else gaz(); } } }``````
Its ok Jesc9 :) And thank you for explaining.

@ keskiverto: This is getting way too complicated for me.I'm gonna stay with my simple program :)
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