So close to getting the right output! For loops?

[ECEsasha]

My goal is to take in an input height of h in [1,7] and output a diagonal matrix of 1's with the height h in a 7x7 matrix of zeros.

e.g.

For h = 5, the output should be:

1 0 0 0 0 0 0
1 1 0 0 0 0 0
1 1 1 0 0 0 0
1 1 1 1 0 0 0
1 1 1 1 1 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 0

My output is so close to the triangle of 1's, but it keeps adding one extra row of 1's underneath without the first 0 being a 1. For instance, when I run it for h = 5, I'll get:

1 0 0 0 0 0 0
1 1 0 0 0 0 0
1 1 1 0 0 0 0
1 1 1 1 0 0 0
1 1 1 1 1 0 0
0 1 1 1 1 0 0
0 0 0 0 0 0 0

I would really appreciate any help I can get on how to rid that last row of 1's!

#include <iostream>
#include <cstdlib>
#include <vector>

using std::vector;


int main(int argc, char** argv){

	if(argc < 2){
	        std::cout<< "Please input a height for the triangle \n";
	}

    	int h = atoi(argv[1]);

    	vector<vector<int> > v(7, vector<int>(7,0)); 

	int j = 0;

	for(int i = 0; i < h; i++){
		v[j][i] = 1;
		j=i;
		for(j; j < h; j++){
			v[j][i] = 1;	
		}
	}

	for(int i = 0; i< v.size(); i++){
		vector<int> row = v.at(i);

		for(int j = 0; j < row.size(); j++){
			std::cout<<row.at(j)<<'\t';
		}
		std::cout<<'\n';
	}


	return 0;

}

[MiiNiPaa]

Remove line 21.

[ECEsasha]

Haha, oh my. I feel silly.

Thank you so much! :D