### Count values in array.

I am having an issue with my scoring method for a game called Yahtzee that I am writing for my school. I am using an array to store the final dice roll in but need to find a way to count how many of the ints in the array are of the same value. I know there is a way to do this with a vector using count but we have not learned this yet really and I would have to completely re-do my entire code.

Is there a way to do this? I can't seem to wrap my head around a method to use. Once I have a way to count how many like valued ints are in the array I can figure the rest out.

 ``123456789`` `````` Ex: die[5] = {1,1,1,3,4}; //I want to now count how many of each value there is then store it. int ones = 3; int twos = 0; int threes = 1; int four = 1; int fives = 0; int sixes = 0; ``````

Something like this is what I am aiming for just don't know how to go about it.
You could do something like this:
 ``12345678`` ``````int die[5] = {1,1,1,3,4}; int rolled[6] = {0,0,0,0,0,0}; // This line checks each dice for it's value for (int i = 0; i < 5; i ++) // This line takes the value of each dice, subtracts 1 from it (because it's an // array), and increases that value's count rolled[(die[i] - 1)] ++;``````
 ``123456789101112`` ``````for( size_t i = 0; i < 5; ++i ) { switch( die[ i ] ) { case 1 : // increment ones variable break; case 2 : // increment twos variable break; // ... }``````
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