Using the << and >> Operators on Bits

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It is a way to do it in assembly. The problem with your method is that it is CPU-bound.

Why are we messing with assembly again?

[edit] fixed that italic 'a' to underlined 'a' for readability... :-D [/edit]
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Alright, good thing I got that right. I published it on my blog before anyone confirmed it. ^_^ And if I couldn't understand it, I would've probably gone on to use a bitset, and we don't want to do that...

Anyways, thanks for the help. I'm going to mark this topic as solved now...
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Pages: 12