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// The program should calculate the average, median, and mode of the values entered.
//
//
// Yea I know I don't need all of these
// I just keep reusing the same form as I practice
// An I just remove the code and start new code
#include "stdafx.h"
#include<iostream>
#include <iomanip>
#include <stdio.h>
#include <stdlib.h>
using namespace System;
using namespace std;
int get_mode(int n[], int size, int max);
int main(array<System::String ^> ^args)
{
/*Console::WriteLine(L"Hello World");*/
/*Junk I leave in for testing when my system goes nuts*/
int * students, n, total, med, frank, f ;
float avg;
/*Message to the end user with two line breaks*/
cout << " This is a one month survey? \n\n";
/*We are sending a question to the screen*/
cout << " How many students were surveyed in one month? \n";
cout << " Please only whole numbers no zeros or fractions \n\n";
cout << " Enter value for N : ";
/*We are taking the input from the keyboard*/
cin >> n;
cout << "\n\n"; /*add a line break for visual effect */
/*Error Checker: Making sure that the user is not placing in a number zero or negative number*/
if(n <= 0)
{
/*Message output to the screen if boolean value is true*/
cout << "Invalid number\n";
/*Stopping the screen from closing so the user can see the output*/
system("PAUSE");
return 1;
}
/*Storing the value of the keyboard input for student as 'n' "dynamically allocate array" */
students = new int[n];
/*Starting the count loop */
for(int i = 0; i < n; i++)
//for(f=0; f < i; f++)
{
/*Sending message to the screen to collect values for the place holders set by the value of 'n'*/
cout << "How many movies did student #" << i +1 << " see?\n";
/*Taking the input value for each place holder set by 'n'*/
cin >> students[i];
total += students[i];
/*Adding all the values being entered storing them in the holder 'avg' "calculate the average " */
med += students[i];
}
/*Taking the total count of avg and finding the median value stored; in 'n' that is use for the loop count */
avg = total/n;
med /= n;
/*Sending output to the screen of all the values stored and then divided*/
cout << "\n" << endl;
cout << "\n" << "The value you entered in for N was " << n << "\n\n" << endl;
cout << " Sum of value " << total << "\n" << endl;
cout << " The average is " << avg << " \n" << endl;
cout << " The mode is " << get_mode << "\n" << endl;
/*cout << " get_mode" << get_mode << endl;*/
// Checking to see if it is a even number and moving it up from position zero to get a middle value
if ( n % 2 == 0)
{
n = (n+1)/2;
}
//Checking to see if it is a odd number
else
{
n = (n/2);
}
cout << "\n" << "The median is Number is " << students[n] << "\n" << endl;
// printf("Mode: %d\n", get_mode());
/*Stopping the screen from closing so the user can see the output*/
system("PAUSE");
/*Adding a line break just a habit I do for a good visual effect*/
cout << "\n";
/*Clearing the pointer "dynamically allocated memory holder"
for student */
delete [] students;
return 0;
}
int get_mode(
int n[], /* List of numbers */
int size, /* Size of list */
int max /* Upper range limit */
)
{
int *freq;
int i;
int mode;
// I saw this code and though I would borrow it to see if I could grab the mode of the values being entered
// One issue I know of is if there is not a repeted number then there is not a mode value but it will not compile now.
/* Allocate and zero fill a table */
freq = calloc(max, sizeof *freq); //error here//
/* Increment the appropriate element for each occurrence of a[i] */
for (i = 0; i < 10; i++)
{
++freq[ n[i] ];
}
/* Find the first largest element */
mode = 0;
for (i = 0; i < max; i++)
{
if (freq[i] > mode)
{
mode = i;
}
}
free(freq);
return mode;
}
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