Creating an inverted triangle using **

Last edited on
I've done printing of triangles with nested for loops.

Do you mean this shape?

 ``1234567891011`` ``````for (int row=1; row<=size; row++) { for (int col=1; col<=size; col++) { if (col<=row-1) cout << " "; else cout << "*"; } cout << endl; }`````` ```******* ****** ***** **** *** ** *```

or like this?

 ``1234567891011`` `````` for (int row=1; row<=size; row++) { for (int col=1; col<=size; col++) { if (col<=(size-row)+1) cout << "*"; else cout << " "; } cout << endl; }`````` ```******* ****** ***** **** *** ** * ```
Last edited on
 ``1234567891011121314151617181920`` ``````# include using namespace std; int main () { cout << "Enter a number between 1 and 7 ->"; int nbr;cin >> nbr; for(int i=nbr;i>=0;i--) { for(int j=0;j<(nbr-i);j++) cout << " "; for(int j=i*2;j>=0;j--) { cout << "*"; }cout << endl; } return 0; }``````
Wildblue, like the second image you posted.
is the "for" statement the same as using "while"?
I edited the post with a code snippet. Basically you can find the relationship between the numbers for the current row number, current column position and the full length of the triangle.

Row 1 - print a * position 1 through position 7 (full length(7) - row#(1) +1)
Row 2 - print a * position 1 through position 6 (full length(7) - row#(2) +1)
.
.
Row 6 - print a * position 1 through position 2 (full length(7) - row#(6) +1)
Row 7 - print a * position 1 only (full length(7) - row#(7) + 1)
Topic archived. No new replies allowed.