Help with calculator

[moot1]

How would i make it so where if the person enters 1 the program ends?

#include <iostream>

using namespace std;

int main()
{
    char operation;
    double number;
    double number2;
    double total;

    cout << "This is a calculator where you have to enter the problem in the order you want it solved. \n";
    cout << "Enter the first number in the problem: ";
    cin >> number;
    cout << "\n Now enter the operation: ";
    cin >> operation;
    cout << "\n Now enter the second number: ";
    cin >> number2;

    switch(operation){
        case '+':
        total = number + number2;
        cout << " \nYour current total is: " << total;
        break;

        case '-':
        total = number - number2;
        cout << " \nYour current total is: " << total;
        break;

        case '*':
        total = number * number2;
        cout << " \nYour current total is: " << total;
        break;

        case '/':
        total = number / number2;
        cout << " \nYour current total is: " << total;
        break;
    }

    label:

    cout << " \n Now enter the next operation or enter 1 if your problem is already solved: ";
    cin >> operation;
    cout << "\n Now enter the next number: ";
    cin >> number;

    switch(operation){
        case '+':
        total = total + number;
        cout << " \nYour current total is: " << total;
        break;

        case '-':
        total = total - number;
        cout << " \nYour current total is: " << total;
        break;

        case '*':
        total = total * number;
        cout << " \nYour current total is: " << total;
        break;

        case '/':
        total = total / number;
        cout << " \nYour current total is: " << total;
        break;
    }
    goto label;

    return 0;
}

[LB]

Add another case label for '1' between lines 68 and 69?

Also, use a loop structure instead of goto.

There is a simpler way to do this with loops that does not involve duplicating code as you have done ;)