Help1

[bozz51]

How can I display my eight numbers in three columns?
12
13
15
17
18
15
18
19

I get them to display correctly I just can't seem to get them in three columns
I was thinking if ((x + 1) % 3 == 0) but it doesn't work.

#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;

int main()
{
	ifstream fin;
	fin.open("data.txt");
	int x = 0;
	int counter = 0;

	while (fin >> x)
	{
		
		cout << x <<"\t";
		counter = counter += 1;

	}
	
	cout << "Total numbers:" << counter << endl;
	system("pause");


}

[Stephanie16]

See if this would help

http://bytes.com/topic/c/answers/656497-cin-cout-rows-columns

[bozz51]

Didn't help...

[long double main]

Using your idea:

cout << counter;
if ((counter + 1) % 3 == 0)
    cout << '\n';
else
    cout << ' '; // I don't like using tabs to align things 

Edit: oops

[RadWayne]

You might be able to use setw

http://www.cplusplus.com/reference/iomanip/setw/

[Chervil]

Test the counter, not x.

    int x = 0;
    int counter = 0;

    while (fin >> x)
    {
        if ((counter>0) && (counter%3==0))
            cout << endl;
        cout << setw(3) << x;
        counter++;
    }
    cout << endl;

The test of (counter>0) is simply to avoid a blank line at the start, but you might omit this if you like.

[bozz51]

Chervil,
That did the trick! Thank you, now why would counter work and not just x?

[Chervil]

why would counter work and not just x?

Well, counter behaves in a predictable and known way, whereas the values of x are all over the place. More relevantly, in order to arrange the numbers into three columns, you need some way of counting how many values have been printed in a column, and the counter fulfils exactly that requirement.

[bozz51]

Chervil,
Again thank you...