Allocating normal variables (int ?) ?

[DatIncredibleGuy]

Hi, I getting familiar with allocating, but all I have been allocating is arrays

        int numberstocount, numbers[1];
	int* p_numbers = numbers;

	cout << "enter number to be counted : ";
	cin >> numberstocount;

	p_numbers = new int[numberstocount];

I have tried allocating normal variables (variables that hold simple numbers).
But I have been getting same results.

I use this is the code :

	int x = 20;
	int* p = &x;

	cout << x << endl;
	
	p = new int[100];

	cout << x;

can I allocate normal variables ? I know I can, but how ? am I doing something wrong ?

[MiiNiPaa]

Allocating arrays:

int count;
std::cout << "How lagrge should array be?\n";
std::cin >> count;

int* array = new int[count];

//Somewhere later
delete[] array;

Allocating single variable:

int* var = new int;

//Somewhere later
delete var;

[DatIncredibleGuy]

still getting same result. can you make a simple program that work ? like this

int main()
{
	int x = 20;
	int* p = &x;

	cout << x << endl;
	
	p = new int;

	cout << x;

	cin.ignore();
	cin.get();
	return 0;
}

^this don't work,

[MiiNiPaa]

It work. Exactly like it should. What your problem with it?

If you want another behavior, tell and I will show you.

BTW, whay do you need line 3? You do not access x through p, why are you assigning its address to p?

If you want to change values through pointer:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22

int main() { int x = 20; std::cout << " x = " << x << '\n'; int* p = &x; *p = 10; std::cout << " x = " << x << '\n'; std::cout << "*p = " << *p << '\n'; p = new int; *p = -100; std::cout << " x = " << x << '\n'; std::cout << "*p = " << *p << '\n'; *p = 25; std::cout << " x = " << x << '\n'; std::cout << "*p = " << *p << '\n'; delete p; //NEVER forget to delete allocated memory std::cin.ignore(); std::cin.get(); }

x = 20 x = 10 *p = 10 x = 10 *p = -100 x = 10 *p = 25

http://ideone.com/dPHVI5