Solutions Needed........

[r 4 raja]

#include<iostream.h>
#include<conio.h>
void main()
{
int x[5]={1,2,3,4,5}, y[5]={5,4,3,2,1}, result[5]={0,0,0,0,0};
int i=0;
while(i++<5)
result[i]=x[i]-y[i];
clrscr();
cout<<"\n The contents of the aray are:\n";
i=0;
do
{
cout<<"\t"<<x[i]<<"\t"<<y[i]<<"\t"<<result[i]<<"\n";
i++;
}
while(i<5);
getch();
}

output:
The contents of the array are:
1 -1 0
2 4 -2
3 3 0
4 2 2
5 1 4


The above program is executed the following output are displayed. How this executed plz explain this. Why first element of the array are displayed

1 -1 0 --> Explain this step only

[booradley60]

That's not the output I got. I saw

1    5    0
2    4    -2
3    3    0
4    2    2
5    1    4

and a crash. The problem is this line: while(i++<5) When i is 0, the condition '0<5' is evaluated, but then the '++' is applied and the loop body uses i=1. What happens when i=4? '4<5' evaulates as true, then '++' is applied, and the loop body uses i=5. However, an index of 5 falls out of bounds for all the arrays you're using.

[ne555]

> That's not the output I got
undefined behaviour is undefined

[r 4 raja]

I got the following output

1 -1 0
2 4 -2
3 3 0
4 2 2
5 1 4

[AbstractionAnon]

You're not getting the correct results because you're not referencing your arrays correctly as booradley60 already explained.

int i=0;
while(i++<5)
    result[i]=x[i]-y[i];

This loop will reference array elements [1] - [5]. Your array elements are [0] - [4]. A reference to [5] is UNDEFINED.

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