Testing each array

The program below will generate 5 random numbers and asks the user to enter 5 numbers to see how many numbers he guessed right. What i need help is how do i test each array that the enter inputted, with the numbers the computer generated, with a loop without having both of the index increasing so i can test each individual index with the computer generated numbers 5 times before moving on to the next index for the user inputted index

 ``1234567891011121314151617181920212223242526272829303132`` ``````srand(time(0)); int number[5]; //store each index with a random number for (int x = 0; x < 5; x++) { number[x] = rand()%5; } int userNumber[5]; int right = 0; cout << "The computer just generated 5 numbers. Lets test your luck. Please enter 5 numbers: "; //input for user 5 numbers for (int x = 0; x < 5; x++) { cin >> userNumber[x]; } //the test for (int x = 0; x < 5; x++) { if (userNumber[x] == number[x]) { right++; } } //the random numbers for (int x = 0; x < 5; x++) { cout << number[x] << ','; } //results cout << "You got " << right << " right!"; cout << "The numbers were: ";``````

i can write the test like this:
for (int x = 0; x < 5; x++)
{
if (userNumber[0] == number[x])
{
right++;
}

if (userNumber[1] == number[x])
{
right++;
}
if (userNumber[2] == number[x])
{
right++;
}
}
where i state out the index number but it would take forever if i had 10000 values.
Last edited on
You could use a nested for loop:

 ``123456`` ``````for(int x = 0; x < 5; x++) for(int y = 0; y < 5; y++) { if(userNumber[i] == number[j]) right++; }``````

But I'm not really sure this is what you want--if the user matches all five numbers, he will be told he got 25 right. What behavior are you trying to produce?
Ohhh that worked. ty
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