syntax funtion problem

[skyrunner83]

Good morning to everyone,
I have a problem for interpret a source code in c++. Can someone help to me.
What mean:

  scope_abc::function_name ( ) (&a,&b);

Why are there 4 parentheses? function ( ) (...)

The realy name of the function in the source code is 'operator'.

Thanks to everyone

[Peter87]

I guess scope_abc::function_name() returns an object that has operator() defined.

namespace scope_abc
{
	struct C
	{
		void operator()(void*, void*){}
	};
	
	C function_name()
	{
		return C();
	}
}

[skyrunner83]

I'm sorry but I have not explained correctly my problem or I didn't understand "the solution".

I'm inside the class 'abc' (abc.cc file)

void abc::operator ()(....) {
	int a;
	c = ....
	........
}

But in the same file I don't have the funtion

object_type abc::operator() {
        ....
	return ...;
}

thank you very much