Calculator

Hi there, I made this code up but I don't know why the result didn't come up with decimal its just an integer number even I made the data type float / double?

I also wanted from the code to start again if it gives the "Error"
look at line 68 if you didn't get what I mean

*note*
This code is just a start for me..

Thanks.
regards..

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#include "stdafx.h"
#include <iostream>

using namespace std;

int addNums(float x, float y){
	float answer = x + y;
	return answer;
}

int addNums1(float a, float b){
	float answer = a - b;
	return answer;
}

int addNums2(float c, float d){
	float answer = c / d;
	return answer;
}

int addNums3(float e, float f){
	float answer = e * f;
	return answer;
}


int main()
{
	float n1, n2;
	int num;
	cout << "Please enter a number: ";
	cin >> n1;
	cout << endl;

	cout << "Please enter a number: ";
	cin >> n2;
	cout << endl;

	cout << "Please choose your mathematical operation: " << endl;
	cout << "Press \n 1 for addition \n 2 for subtraction \n 3 for division \n 4 for multiplication \n";
	cin >> num;

	if (num == 1){
		cout << "The result is: ";
		cout << addNums(n1, n2);
		cout << endl;
	}

	else if (num == 2){
		cout << "The result is: ";
		cout << addNums1(n1, n2);
		cout << endl;
	}

	else if (num == 3){
		cout << "The result is: ";
		cout << addNums2(n1, n2);
		cout << endl;
	}

	else if (num == 4){
		cout << "The result is: ";
		cout << addNums3(n1, n2);
		cout << endl;
	}

	else
		cout << "error";

	system("pause");

	return 0;
}
Because you accidentally left the return types as int.

By the way, prefer using double instead of float - only use float if you need to store a lot of them and you don't mind losing precision.
you mean in lines 6, 11, 16, 21??
okay solved.. thank you, Sir
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