Problem in solving even-odd number

[abdalimran]

You are given a nonnegative integer number. The number contains not more than 100 digits. Then you have to check if the number is even or odd.

I wrote the following code for this problem..but still getting wrong answer. :(

#include <iostream>
#include <string>
#include <cstdlib>

using namespace std;

int main()
{
    int t;
    cin>>t;

    while(t--)
    {
        string str;

        getline(cin,str);

        if(str.length() <= 100)
        {
            unsigned long long num = atoi(str.c_str());

            if(num%2==0)
                cout<<"even"<<endl;
            else
                cout<<"odd"<<endl;
        }
    }


    return 0;
}

#include <iostream>

using namespace std;

int main()
{
    int t,num;
    cin>>t;

    for(int i=1; i<=t; i++)
    {
        cin>>num;

        if (num & 1)
            cout << "odd" << endl;
        else
            cout << "even" << endl;
    }

    return 0;
}

Where is the problem? Why I am getting wrong answer?

[LB]

You only ever need to examine the last digit in a number to see if it is even or odd.

There is no native integer type in C++ large enough to hold a 100 digit integer.