Don't understand how the code is working.

[abdalimran]

Input and Output

Input to your program will consist of a series of lines, each line containing multiple words (at least one). A ``word'' is defined as a consecutive sequence of letters (upper and/or lower case).

Your program should output a word count for each line of input. Each word count should be printed on a separate line.

Sample Input

Meep Meep!
I tot I taw a putty tat.

Sample Output

2
7

The solution is given here...I can't understand how the code is working? How it is ignoring the dots, detecting the words and counting?

#include <iostream>
#include <string>

using namespace std;

int main()
{
    string s;
    int c=0;

    getline(cin,s);

    for(int i=0; i<s.length(); i++)
    {
        if(s[i]>='A' && s[i]<='Z' || s[i]>='a' && s[i]<='z')
            c++;
        for(;(s[i]>='A' && s[i]<='Z')||(s[i]>='a' && s[i]<='z') && i<s.length();i++){}
    }

    cout<<c<<endl;

    return 0;
}

[Smac89]

The code is equivalent to this:

#include <iostream>
#include <string>
#include <ctype>

using namespace std;

int main()
{
    string s;
    int c = 0;

    getline(cin,s);

    for(int i=0; i<s.length(); i++)
    {
        if(isalpha(s[i])
            c++;
        for(; i < s.length() && isalpha(s[i]); i++);
    }

    cout<<c<<endl;

    return 0;
}

As you can see, the code only checks for letters of the English alphabet in the inner loop and exits the inner loop once it finds something that is not a letter.

[dhayden]

You may be getting tripped up by the fact that i is incremented in two places. For what it's worth, this is pretty ugly code to me.

[abdalimran]

But how it is detecting the spaces and counting the words?
its not clear to me.

[dhayden]

When it sees a letter at line 15 it is at the beginning of a word and it increments c (the count of words). Line 17 then skips subsequent letters until it hits a non-letter. That where it detects spaces, along with anything else that isn't a letter.