advanced random number generator help

[xxgixxx]

hello ,i need help with this number generator.
i want the program to tell me when i am close to the number he picked.
i.e : if the program generated 40 as a random number , if i type 35 , or 45 ,
the program will tell me that i am close to the number he picked.

  #include <iostream>
  #include <cstdlib>
  #include <ctime>

using namespace std;
int main ()
{
  int numpicked = 0;//stores the number the user guesses
  int guessnum;//stores the number of tries 
  int numgenerated;//the generated number

cout<<"welcome ! i have picked a number between 1 and 100";
srand ((int)time(NULL));
numgenerated = rand() % 100+1;

for (guessnum=0 ; numgenerated != numpicked ; guessnum++)
{
cout<<"what would you like to guess? \n";
cin>>numpicked;

if(numpicked < numgenerated)//checks if the number picked is low

  cout<<"too low \n";

else if (numpicked > numgenerated)//checks if the number picked is high

  cout<<"too high \n";

}
cout<<"you guessed it! it took you "<<guessnum<<" guesses \n";

return 0;
}

[PrivateRyan]

a while loop would be more fitting than a for loop, given the logic of the program. Increment guessnum every time you go through the loop, and set a condition to break out of the loop if the answer is found. Here is some psuedo code:

while (guess is not answer)

if guess < answer
say something
else
say something

increment guessnum
repeat

say something

[xxgixxx]

it could be better but you didn 't answer my question.

[Zhuge]

xxgixxx wrote:

it could be better but you didn 't answer my question.

What was your question? I don't see one.

[xxgixxx]

My question is that I want the program to tell me when I am close to the random number not just lower or greater

[Zhuge]

What problem were you having doing that? Was there something about the code that you didn't understand that was making it hard for you to figure out what to do?