howto multiply, ignore whitespace on cin

[Garbeld]

Whee... hello.
I'm compiling with Dev-C++'s default compiler (MingW, as I understand it), on Windows XP. I doubt either of these are significant, but oh well...
Two small problems here.

Firstly, multiplication:
Right now, I've got

char[9] pdat;
loadedfile.read(pdat, 9);
int tdat;
(start for loop)
tdat = pdat[x]*(2^7-x)

From what my friend says, my problem(getting seemingly non-sensical values) is asterisk's double-meaning, as multiplication and "pointer" (a concept I'm not familiar with).
If that's the case, how do I tell the compiler that I want to multiply?
If it's not the case... I'm getting non-zero results where pdat[x]=0, and non-powers of 2 where pdat[x]=1 (loadedfile is just a text document of 1s and 0s), and I have no idea what's going on.

Second, I have several places in my program where it cin's a string used for a filename. However, it breaks when encountering whitespace.
I've tried:

cin >> noskipws;
cin >> filename;

and
cin.get(filename);
as seem to be suggested wherever I found online, but the first one doesn't seem to make any difference, and the second makes my compiler angry ("108 C:\...\main.cpp no matching function for call to `std::basic_istream<char, std::char_traits<char> >::get(std::string&)' ")

[Bazzy]

1) 2^7 means 2 xor 7, use the pow function ( http://www.cplusplus.com/reference/clibrary/cmath/pow/ )
2) Try getline(cin,filename);, this reads until a newline character ( '\n' ) is found - you can change the delimiting character if you wish

[Garbeld]

1) 2^7 means 2 xor 7, use the pow function ( http://www.cplusplus.com/reference/clibrary/cmath/pow/ )

Ah, I thought of that, but also failed to find anything on powers in C++.
Nonetheless, that accounted for, I'm still getting some rather perplexing results.

    cout << pdat[x] << " ";
    cout << pdat[x]*pow(2.0, x) << " -- ";

yields:

0 48 -- 1 98 -- 0 192 -- 0 384 -- 0 768 -- 1 1568 -- 0 3072 -- 1 6272

2.

2) Try getline(cin,filename);, this reads until a newline character ( '\n' ) is found - you can change the delimiting character if you wish

  string newname;
  cout << "new filename:";
  getline(cin, newname);
(intermediate code)
cout << "finished.  Restarting...\n\n";

results in

new filename:finished. Restarting...

I'm inclined to think I'm missing something obvious on either of these, here, but...

[Bazzy]

1) Can you post some more code of that part? Those two lines should work

2) That is because you are getting input with >> before getline. Add cin.ignore(); before getline, it will remove the '\n' character that >> leaves on the stream. To get input from cin in a better way see http://www.cplusplus.com/forum/articles/6046/

[Garbeld]

1) Can you post some more code of that part? Those two lines should work

   if(cursel == 3){
  string newname;
  cout << "new filename:";
  cin.ignore;
  getline(cin, newname);
  ofstream newfile((curdir+newname).c_str());
    for(int runs = loadedsize/9; runs > 0; runs=runs-1){
   char pdat[9];
   loadedfile.read(pdat, 9);
   int tdat;
     for(int x = 0; x < 8; x = x+1){
    cout << pdat[x] << " ";
    cout << pdat[x]*pow(2.0, x) << " -- ";
     }
   cout << "\n";
   char udat = tdat;
   newfile << udat;
    }
   }

2) That is because you are getting input with >> before getline.

I'm not sure what you mean by that. There were no instances of >> in my program, after I did what you said.
Adding cin.ignore; gives me compile error: "statement cannot resolve address of overloaded function".
I'm not sure what's different in my code from what that in the article you linked (which I tried compiling and running; the article's code worked).

[Bazzy]

You forgot function parentheses after cin.ignore
And pdat[x] is a character, this means that you are doing operation on the ASCII values, not on the actual numbers ( eg '1' = 49 )