Repeating entire program

[TieRein]

I would like to have my entire program to repeat a single time without user input. How could I do this with both main and foo? I know how to repeat a program when there is just main but not when there are two functions.

int foo()
{
	int a,
		b,
		c,
		d;
	cout << "Please enter three numbers: " << endl;
	cin >> a;
	cin >> b;
	cin >> c;
	d = a + b + c;
	return d;
}
int main()
{
	int Sum = foo();

	cout << "Your sum of these numbers is: " << Sum << "\n" << endl;

	return 0;
}

[Bdanielz]

based on your description this answers your question, but I am not sure if this solves your problem.

#include <iostream>

using std::cout;
using std::cin;
using std::endl;


int foo()
{
    int a,
    b,
    c,
    d;
    cout << "Please enter three numbers: " << endl;
    cin >> a;
    cin >> b;
    cin >> c;
    d = a + b + c;
    return d;
}
int main()
{
    bool first_run = true;
    while (first_run) {
        int Sum = foo();
        
        cout << "Your sum of these numbers is: " << Sum << "\n" << endl;
        first_run = false;
    }
    
    int Sum = foo();
    
    cout << "Your sum of these numbers is: " << Sum << "\n" << endl;
    
    
    return 0;
}

[TieRein]

Its exactly what I needed. However I dont understand how this works. Do you mind explaining to me whats going on in line 25 - 29? How does it know to go back up and run foo again?

[Bdanielz]

 while (first_run) {
        int Sum = foo();
        
        cout << "Your sum of these numbers is: " << Sum << "\n" << endl;
        first_run = false;
    }

in other words

this = true;
while (this = true)
{
run this code.
then set this = false.
}

so it sets "first_run" to true.
while loop works while "this" is true
then once while loops executes it sets "this" to false...
then it does not run again.

hope that makes sense.

[Irhcsa]

TieRein line 24 he creates a bool named first_run and sets it to true.

Line 25: While loop. Stating that WHILE the bool you created is "true" what ever follows will keep happening until it's turned to false.

Line 26: Is stating that the integer named "Sum" is equal to integer named "foo()"

Line 28: The CMD will say "Your sum of these numbers is: "your sum"

Line 29:: Turns your bool first_run to false, shutting down the loop.

[TieRein]

What causes foo to run again? It it when it calls on "int Sum = foo();"?

What I dont understand is how its not just taking the return number from foo twice. How is foo running twice?

[cire]

Its exactly what I needed. However I dont understand how this works. Do you mind explaining to me whats going on in line 25 - 29? How does it know to go back up and run foo again?

The code in question is a loop which only runs once. It is a bit of obfuscation.

The main is equivalent to:

int main()
{
    int Sum = foo();
        
    cout << "Your sum of these numbers is: " << Sum << "\n" << endl;
    
    int Sum = foo();
    
    cout << "Your sum of these numbers is: " << Sum << "\n" << endl;
    
 }

Something more useful might be:

int main()
{
    const unsigned times_to_execute = 2 ;
    for (unsigned i=0; i<times_to_execute; ++i)
    {
        int sum = foo();
        cout << "Your sum is: " << sum << '\n';
    }
 }