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How to grab separate inputs and count the vowels

uchi240 (16)
So, I'm trying to figure out how to take a certain amount of inputs and grabbing those inputs and checking to see if any of those characters are vowels. No strings. Please help!!!!
LB (13399)
Could you explain a bit more? What have you written so far?

What does "No strings" mean? Surely you are not forbidden from using one of the most fundamental classes in C++?
uchi240 (16)
Im sorry for not being specific. This is what I have so far...
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#include <iostream>

using namespace std;

int main()
{
    char x1, x2, x3, x4, x5, x6;
    char answer;
    
    cout << "Enter 6 characters." << endl << endl;
    
    cout << "Enter first character: ";
    cin >> x1;
    cout << "Enter second character: ";
    cin >> x2;
    cout << "Enter third character: ";
    cin >> x3;
    cout << "Enter fourth character: ";
    cin >> x4;
    cout << "Enter fifth character: ";
    cin >> x5;
    cout << "Enter sixth character: ";
    cin >> x6;


Now, I'm trying to figure out how many are vowels. Should I use a for loop or while loop or if statement???
Last edited on
anup30 (968)
use for loop for the input.
JoshuaMostafa (29)
Your best bet is to use a switch statement with one case for each vowel, then default for non-vowel.

Second step is to wrap up everything in a do-while loop to allow users to run the program multiple times to be able to enter chars more than once.

I did not compile this code, but it should work:

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#include <iostream>

using namespace std;

int main()
{
    char input;
    char x1, x2, x3, x4, x5, x6
    bool done = false;
    
    do {
        cout << "Enter 6 characters" << endl << endl;
		
        cout << "Enter first character: " << endl;
        cin >> x1;
        cout << "Enter second character: " << endl;
        cin >> x2;
        cout << "Enter third character: " << endl;
        cin >> x3;
        cout << "Enter fourth character: " << endl;
        cin >> x4;
        cout << "Enter fifth character: " << endl;
        cin >> x5;
        cout << "Enter sixth character: " << endl;
        cin >> x6;
        
        int count = 0;
        switch (x1) {
               case 'a': count++; break;
               case 'i': count++; break;
               case 'e': count++; break;
               case 'u': count++; break;
               case 'o': count++; break;
               } 
		   
		switch (x2) {
               case 'a': count++; break;
               case 'i': count++; break;
               case 'e': count++; break;
               case 'u': count++; break;
               case 'o': count++; break;
               } 
			   
		switch (x3) {
               case 'a': count++; break;
               case 'i': count++; break;
               case 'e': count++; break;
               case 'u': count++; break;
               case 'o': count++; break;
               } 
			   
        switch (x4) {
               case 'a': count++; break;
               case 'i': count++; break;
               case 'e': count++; break;
               case 'u': count++; break;
               case 'o': count++; break;
               } 
			   
		switch (x5) {
               case 'a': count++; break;
               case 'i': count++; break;
               case 'e': count++; break;
               case 'u': count++; break;
               case 'o': count++; break;
               } 
			   
		switch (x6) {
               case 'a': count++; break;
               case 'i': count++; break;
               case 'e': count++; break;
               case 'u': count++; break;
               case 'o': count++; break;
               } 
			   
			   cout << "Number of vowels is " << count << endl;
			   
			   cout << "Exit? (Y/N)";
			   cin >> input;
			   if (input == 'y') {
				   done = true;
			   }
			   
        } while (!done)
    
    system ("PAUSE");
    return 0;
    
}
Last edited on
LB (13399)
Or, you could count the occurrences of all characters in a std::map and then just look at how many of each vowel there are. It would be a lot less code.
anup30 (968)
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#include <iostream>
int main() {	
  char ch[6];
  char vow[6] = {'a','e','i','o','u'}; 
  int count=0;
  for(int i=0; i<6; i++){
    std::cout << "enter character " << i+1 << ": ";
    std::cin >> ch[i];
    ch[i]=tolower(ch[i]);
    for(auto x: vow) if(x==ch[i]) count++;    
  }
  
  std::cout << "total vowels inputed = " << count << "\n";
  
  for(auto x: vow) {
    count=0;	
    for(auto y: ch) if(x==y) count++; 
    if(count) std::cout << x << ": " << count << "times\n";  
  }
	
return 0;	
}
LB (13399)
That works, but it's pretty awkward.
Last edited on
anup30 (968)
letter counter by map
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#include <iostream>
#include <map>
using std::cin;
using std::cout;
using std::string;
using std::map;

int main() {	

  string s;
  map<char, int> letters;   

  cout << "enter a character string: ";
  getline(cin, s);    
  
  for(auto &x: s){
  	x= tolower(x);
  	++letters[x]; // map operator[]
  }
  
  for(auto x: letters){
  	cout << x.first << " " << x.second << "\n";
  }
  
return 0;	
}
uchi240 (16)
Thanks everyone for the help!!!!!
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