C++ How can i output all the items in this program

[WDman420]

I am having trouble doing my homework assignment I am almost done but in that program I can not figure out how to output all of the users purchases. I dumb down my homework assignment where its still rotatable to the same problem I am having with the homework assignment.I also dont want them to think i just copied and pasted from the internet. I want my code display to display all his purchase like a receipt from a store . I tried the for loop and i like that

 #include <iostream>             // provides:  cout, cin
#include <iomanip>              // provides:  setw
#include <limits>
// setting up the environment
  using namespace std;


bool run = true;
int Item;
double price;
int user_Item_Choice ;
string  UsersYorN;
int count = 1;
bool True1 = true;
bool True2 = true;
void enterItemNum();
void readItems();
void usersYesOrNo();
int main()
 {
 	
 
 while (run == true){
 	 while (True1 == true){
	  
	  enterItemNum();
}
 while (True2 == true){
 
 usersYesOrNo();
}
}
 system("pause");
 return 0;
}


void readItems(){

	cout <<"Item 1: $4.00\n";
	cout <<"Item 2: $5.50\n";
	cout <<"Item 3: $6.50\n";
	cout <<"Item 4: $7.00\n";
}

void enterItemNum()
{
  readItems();
	cout << "\nPlease choose the item number from the menu above: ";
	if (!(cin >> user_Item_Choice )){
			cout<< "Error this is not a number please try again but this time enter number!\n\n";
	cin.clear();
	cin.ignore(numeric_limits<streamsize>::max(), '\n');
	enterItemNum();	
	True1 = true;
        
	}
	else if (user_Item_Choice >= 1 && user_Item_Choice <= 4 ) 
	{
	
	switch(user_Item_Choice)
	{
	 case 1: cout <<"Item 1: $4.00\n";
	Item = 1;
	  price = 4.00;
	 break;
	 case 2: cout <<"Item 2: $5.50\n";
    Item =2;
	price = 5.50;
	break;
    case 3: cout <<"Item 3: $6.50\n";
		    Item =3;
		 price = 6.50;
	break;	
	case 4: cout <<"Item 4: $7.00\n";
    Item =4;
		price = 7.00;
	break;
	defualt:
		break;
		}
		True1 = false;
		True2 =true;
		
	}
else 
{
 cout<<"Please enter a number 1 - 4 that represent the item that you wanted to buy.\n\n\n";
	readItems();
	True1 = true;
}

} 


void usersYesOrNo()
{	 
cout << "Would you like to buy more items? if yes enter [y] otherwise enter [n]: ";
	 cin>> UsersYorN;
	if (UsersYorN == "Y" || UsersYorN == "y"||UsersYorN == "yes"|| UsersYorN == "Yes" || UsersYorN == "YES"  )
	{
		count++;
	
				True1 = true;
				True2 = false;
				run = true;


		}
	else if (UsersYorN == "N" ||UsersYorN == "n" ||UsersYorN == "no" || UsersYorN == "No" ||UsersYorN == "NO" )
 { True1 =false;
 True2 =false;
    run = false;
    
 // I want to display all the strings inputed. i know it a loop but i have  no idea 
 // what loop to use

cout<< " Your purchased items \n";
for (int i = 1; i<=count ; i++){
 cout << "Item#"<<Item << "   $"<<price <<"\n" ;
}


 }
  else 
 {
 cout << "****Error: Please enter Yes or No!\n\n";
 True2 =true;

 }

 }

	

[AbstractionAnon]

If you want to keep track of multiple items purchased, your're going to need an array (or vector).

Line 120: You're outputting the same item and price every time through the loop. This is where you need to get price and item from an array.

[WDman420]

can you show me an example on how i would do that

[AbstractionAnon]

 
#include <vector>
#include <string> 
using namespace std;

struct Item 
{  double price; 
    string descr; 
};

vector<Item>  items;

void add_item (double price, const string & descr)
{  Item  item;
 
    item.price = price; 
    item.descr = descr; 
    items.push_back (item);
}

void print_items ()
{  for (unsigned i=0; i<items.size(); i++)
        cout << items[i].descr << items[i].price << endl;
}