Help with the question

[tesla2015]

Hi, this is my first time learning programming and i am just trying out some practice questions but having some trouble with this question.Thank You. Your help will be very much appreciated.


Write a program that prints all of the numbers less than 2000 that are evenly divisible by 10. The first few programs are 10 20 30 ....

[cnoeval]

Show your attempt and explain where you are stuck...

[anup30]

use a for/while loop.

[TarikNeaj]

Use a for-loop and make it run between 0 and 2000. Then ask if "i" or whatever you call the index inside the for-loop leaves 0 as remainder after you've divided it by 10, if so, print it out. Becuase only numbers that are evenly divided by 10 has a remainder of 0.

[anup30]

for(int i=0; i<=2000; i+=10) cout<< i <<endl;

[TarikNeaj]

@anup30

while that does print things out correctly. It is not the best way of doing it. That code is hard coded. This is better

for (int i = 1; i <= 2000; i++) 
	{
		if (i % 10 == 0) // Divides i by 10 and checks if it leaves 0 as remainder.
						// Only numbers that are evenly divided by 10 has 0 as remainder.
			cout << i << endl;
	}

[anup30]

hard coded ??

how is it hard coded if it uses less cpu time ?

[tesla2015]

@tarikneaj..we haven't done if statement in class so far so is it possible to do it just using for loop?

[TarikNeaj]

@Anup30

I might have gotten the term wrong (hard coded) Sorry about that. I think I meant more like, yours just directly does it, while the code I provided actually checks everything and calculates.

@tesla2015

Yes. If you want to do it without using if statements. Then you do it like @Anup30 Suggested.

for (int i = 10; i <= 2000; i+=10) // i = 10 so it doesnt print out 0.
	{
		cout << i << endl;
	}

[anup30]

there is mention of lower bound in the problem. i.e -50 is evenly dividable by 10.(result =-5; remainder =0;)

[TarikNeaj]

@anup30 I dont understand what you're trying to say?

Yes, -50 divided by 10 leaves 0 as a remainder. But he only wanted positive numbers.