Infix to postfix converter
I write a infix to postfix converter 1st time by stack... but cant get correct ans. ( My input no include " ( ) " blacket ~)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
|
#include <iostream>
#include <stack>
#include <string>
#include <cctype>
#include <string.h>
#include <stdlib.h>
using namespace std;
bool isOperator (char *);
bool isHigherthan (char, char);
char atoc (char *);
int main()
{
char exp[3];
stack <int> s;
char sym;
cout << " Enter the Infix equation"<<endl;
cin >> exp;
while (strcmp(exp,";"))
{
if (isOperator (exp ))
{
sym= atoc (exp);
if (s.empty())
s.push (sym);
else if ( isHigherthan( sym , s.top( ) ) )
{
cout << sym;
}
else {
int k = s.top();
s. pop ();
s.push (sym);
s.push (k);
}
}
else
cout << exp << " " ;
cin >> exp;
}
while (!s.empty ( ))
{
cout << s.top( ) << " " << endl;
s.pop();
}
return 0;
}
bool isOperator (char *tmp)
{
if (!(strcmp(tmp,"+"))||!(strcmp(tmp,"-"))||!(strcmp(tmp,"*"))||!(strcmp(tmp,"/")))
return true;
else
return false;
}
bool isHigherthan (char opt1 , char opt2)
{
if ((( opt1 != '*') || ( opt1 != '/')) && ((opt2 != ' +') || (opt2 != '-')))
return true;
else
return false;
}
char atoc( char *str)
{
return str [0];
}
|
input 9 + 2 * 4
i need a output as 9 2 4 * +
Topic archived. No new replies allowed.