a program that flips integers

[shahd95]

I was asked to write a program that prompts the user to enter a 3-digit number, the program flips & displays the number.
for example: input (286) .. output (682)
input (690)... output (96)---> without the (0)

my program works well when inputting an integer that doesn't have a zero at the end of it (e.g. 286) but when I input (690) it displays (096) and not (96).

what should I add to my code in order to prevent the program from displaying the 0.

#include<iostream>
using namespace std;
int main()
{
   int n1, rn1, n2, n3, num;
   cout<<"Enter a 3-digits postive integer: ";

   cin>> num;

   n1 = num/100;
   rn1 = num%100;
   n2 = rn1/10;
   n3 = rn1%10;

   cout<<"The flipped value of "<<num<<" is "<<n3<<n2<<n1;

   return 0;
}

[LB]

Use the same math you already know to recombine the digits back into a number again - then just print that number instead of the individual digits.

[shahd95]

n1 = num/100;
rn1 = num%100;
n2 = rn1/10;
n3 = rn1%10;
flip = n3+n2+rn1+n1;

cout<<"The flipped value of "<<num<<" is "<<flip;

It didn't work.
It displayed 2 digits, but they were incorrect, I entered 268 & it displayed 84.
Thank you though!

[LB]

Your math is wrong. Don't forget you need to multiply each digit by the place you want it to be in. For example, to get a digit in the hundreds place you need to multiply it by 100.