Array Problem with Changes

I'm not sure what to change for it to work for this problem. I'm suppose to make changes to my original code (at the bottom) and make it look like this:
Here is the board:
_ _ _
_ _ _
_ _ _
Please enter a position (0-8): 0
Please enter an X or O: X
X _ _
_ _ _
_ _ _
Please enter a position (0-8): 9
Please follow the directions!
Please enter a position (0-8): 8
Please enter an X or O: A
Please follow the directions!
Please enter an X or O: O
X _ _
_ _ _
_ _ O
^C (stops the program)


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  #include<iostream>

using namespace std;

int main(){

	cout << "Here is the board: "
	int count = 0;
	char array [9];
	while (count < 9){
		cout<<"Please enter an X or O for position "<< count <<": ";

		//user input
		char answer;
		cin >> answer;
		//doing if it is either X or O
		if(answer == 'X' || answer =='O'){
			array[count] = answer;
			count++;
		}
		//If user puts a invalid answer
		else{
			cout << "Please follow the directions!" << endl;
			continue;
		}
	}
	int i;
	//printing the contents
	cout << "Your answers were: ";
		for(i = 0;i < 9;i++){
			cout << array[i];
		}
		cout << endl;
		//how to tell if there is a triple
		int triple = 0;
		  for(i = 0;i < 7;i++){
			  if((array[i]==array[i+1]) && (array[i]==array[i+2]) && (array[i]=='X')){
				  triple = 1;
				  cout << "There is at least one triple X in this data" << endl;
				  //stop after we found the triple
				  break;
			  }
		  }
		   //if no X's triple is found 
    if(triple == 0){
        // haven't fount any X's triple
        cout << "Thee are no triples in this data" << endl;

    }
    return 0;
}
You can use 2D array[3][3]; it will give you a 3X3 square.

when user enter 7 and X, it will assign X to array[2][1], so how?

in C++, when you do integer division 7/3, it will give you 2.(remove all decimal) now you have row number. To get column number you can do 7%3, it will give you remainder 1.

each time when user enter a number and a letter, test them, if they are valid, assign to 2D array.


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