Iostream Problem

[cyborg75]

Hi,

I'm learning ifstream/ostream staff. Once I started I already got a problem, very strange one.
This is my code

#include <iostream>
#include <fstream>
#include <string> 

using namespace std;

int main ()
{
	ifstream infile; 
	infile.open("nombres.rtf");

	//check for error

	if (infile.fail() )
	{
		cerr << "Error opening file" << endl;
		exit(1); 
	}

	int x, y;

	infile >> x >> y; 

	cout << "Num 1: " << x << endl;

	cout << "Num 2: " << y << endl;
	return 0;
}

Normally, there is no problem. In the file nombres.rtf, I wrote 8 on first line, and 9 on second line.
But it tells me :

Num 1: 0
Num 2: 0

Isn't that weird??
Plus, it's only a code I copied from a tutorial !

I would appreciate some help ! :)

[bostock11]

I just posted about the same tutorial. Mine compiles, but doesn't run properly. Are you using Visual Studio?

[S G H]

RTF files aren't really suitable for raw ifstream usage.
Use txt's.

[cyborg75]

S G H : thx for your response, I already tried this before posting, but it doesn't work either...

bostock11 : I'm on mac ! And I don't use IDE !

[tscott8706]

1) What happens when you use a .txt file as S G H suggests?
2) Post both the line that shows you using a txt file, and also show us what is in the txt file.

[S G H]

What does infile.is_open() return?

[cyborg75]

Hi thx tscott8706 and S G H

I wrote this code to test within file.is_open()

#include <iostream>
#include <fstream>
#include <string> 

using namespace std;

int main ()
{
	ifstream infile; 
	infile.open("nombres.txt");

	if (infile.is_open() )
	{
		cout << "ouvert" << endl;
	}

	//check for error

	if (infile.fail() )
	{
		cerr << "Error opening file" << endl;
		exit(1); 
	}

	int x, y;

	infile >> x >> y; 

	cout << "Num 1: " << x << endl;

	cout << "Num 2: " << y << endl;
	return 0;
}

This is what the .txt file contains

8
9

And this is what that return

macbookdeapple:Desktop apple$ ./a.out
open
Num 1: 0
Num 2: 0

[S G H]

#include <fstream>
#include <iostream>

int main()
{
    int a, b;
    if(std::ifstream("numbers.txt")>>a>>b)
        std::cout<<a<<' '<<b<<std::endl;
    else
        std::cout<<"Error"<<std::endl;
}

What does this say?

[cyborg75]

Error

[S G H]

Is the txt file encoded in some weird format?

[cyborg75]

"Text format document"

[TarikNeaj]

Could you show your current code?

Edit: Make sure you get your text files name right

Edit 2: Im not sure how it works when you're not using an IDE but, make sure you're file is stored where its supposed to be, so the compiler can actualy find it.

[cyborg75]

TarikNeaj, thx, yes I already checked all this

int main ()
{
  
	ifstream infile; 
	infile.open("nombres.txt");

	if (infile.is_open() )
	{
		cout << "open" << endl;
	}

	//check for error

	if (infile.fail() )
	{
		cerr << "Error opening file" << endl;
		exit(1); 
	}

	int x, y;

	infile >> x >> y; 

	cout << "Num 1: " << x << endl;

	cout << "Num 2: " << y << endl;
	return 0;

}

[TarikNeaj]

Man thats real weird... Works perfectly fine for me...

[cyborg75]

... yes ... thank you to have checked it all

[LB]

Open the TXT file in a plain text editor like Notepad or Notepad++, not a rich text editor.

[ChrisMoore2]

I think it is down to the path of the input file.
Is the data file in the same directory with the executable?

[LB]

To find out what directory your program is looking for files in, run this code:

#include <fstream>

int main()
{
    std::ofstream("use-this-directory.txt") << "Use this directory for input files.";
}

Then just look for the file.

Some IDEs (especially Visual Studio) make this really confusing.