Question about Boolean

[idenatin]

Hello,

I'm a beginner at C++, and I'm having trouble understanding Boolean:

  ( ! ( true || false) ) //This ends up false
  ( ! ( true || false && false) ) //This ends up false
  ( ! ( ( true || false ) && false ) // This ends up true. 

Now this confuses me. I understand the precedence of the operators, Boolean not being first, then Boolean and, and lastly Boolean or.

For example, the first one, ( ! ( true || false) ). Wouldn't that end up: ( ! ( !true || !false) ). So wouldn't the !false become true? This is where I'm confused.

Thanks in advance!

[LendraDwi]

true||false will result true then its negated with ! so its false
what you ask is !(!true||!false) it'll become !(false||true) because both value is negated with !

[Peter87]

Start with the innermost parenthesis.

(true || false) is true. Not true is false.

!(true || false) -> !true -> false

[idenatin]

Figured it out! Thanks!