Dynamic character array
Attempting to dynamically allocate a name to a character array and getting very confused. Here is where I am at the moment:
Apologies for the awful code and any help much appreciated!
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#include "stdafx.h"
#include <iostream>
int main()
{
using namespace std;
char c = 0;
int i = 0;
int j = 1;
char *str = new char[j];
cout << "Please enter string: ";
while (c != '\n')
{
cin >> c;
str = new char[j];
str[i] = c;
i++;
j++;
}
cout << "Entered string is:" << str << endl;
delete[] str;
return 0;
}
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If you just want to read a string, there is a string class.
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#include "stdafx.h"
#include <iostream>
#include <string>
int main()
{
using namespace std;
cout << "Please enter string: ";
std::string str;
cin >> str;
cout << "Entered string is:" << str << endl;
return 0;
}
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If you know the string won't be longer than some value, you can create a char buffer that large.
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#include "stdafx.h"
#include <iostream>
const size_t max_len = 256;
int main()
{
using namespace std;
cout << "Please enter string: ";
char str[max_len + 1];
for (size_t i = 0; i != max_len; ++i)
{
cin >> str[i];
if (str[i] == '\n')
{
str[i] = '\0';
break;
}
}
cout << "Entered string is:" << str << endl;
return 0;
}
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Or if you really want to dynamically allocate that string:
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#include "stdafx.h"
#include <iostream>
const size_t max_len = 256;
int main()
{
using namespace std;
cout << "Please enter string: ";
char* str = new char[max_len + 1];
for (size_t i = 0; i != max_len; ++i)
{
cin >> str[i];
if (str[i] == '\n')
{
str[i] = '\0';
break;
}
}
cout << "Entered string is:" << str << endl;
delete [] str;
return 0;
}
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