Bitwise AND in a condition

[Binary91]

Hi,

for my enumeration, I need to check the integer sum with a bitwise AND.

class myClass
{
enum myEnum { intOne = 1, intTwo = 2, intThree = 4, intFour = 8};
};

It works all fine like this:

void checkEnum(int intEnum)
{
  if((intEnum & myClass::intOne) > 0)
    ...
  if((intEnum & myClass::intTwo) > 0)
    ...
}

What I don't understand is, why the following also works:

void checkEnum(int intEnum)
{
  if(intEnum & myClass::intOne)
    ...
  if(intEnum & myClass::intTwo)
    ...
}

I mean, as a result of the bitwise AND, I get an integer with the size of the enum, but not a boolean. So why can I check for true and false?

Thank you in anticipation.

Binary

[LB]

When a numeric type is given as the condition, you could imagine that there is an implicit != 0 added to the end of the expression.

[coder777]

if checks for a numeric value != 0, not for bool.

[Binary91]

Ah that is it.. Thank you!