How is the sum of all odd or even numbers found

[kromari]

How do you find the sum of all the numbers output from a loop?

  #include <iostream>

using namespace std;

int main()
{
	int a, b, c;

	cout << "Enter two integers ";
	cin >> a >> b;
	cout << endl;

	while (a > b)
	{
		cout << "The first number must "
			<< "be smaller than the second.";

		cout << "Enter two integers ";
		cin >> a >> b;
		cout << endl;
	}

	

	while ((a = a) && (a < b))
	{
		a = a + 2;
		cout << a << endl;
	}
	
		c = a + a;
		cout << c << endl;
	

	return 0;
}

[PBachmann]

What is a?
What is b?
What is c?
Why do you need 2 integers?
Why does the second have to be larger?
What is the loop being output?

[shamieh]

What is your question kromari?

If your question is: "From a list of integers (numbers), how do you find the sum of all the even numbers and the sum of all the odd numbers respectively?"

Then, here is how:

1) Store the numbers in a vector<int>
2) Use the % (modulo) operator to figure out if the number is odd or even
3) Put the odd numbers in another vector<int>. Put the even numbers in another vector<int>
4) Create a int variable for each vector to store the sum of each vector's elements.

Literally all that's left is to store the sum of each vector in it's respective sum variable

[miah612000]

num % 2 = 0
else
num % 2 != 0

to find odd or even and then total them?