how to outout 0

[machegache]

hi i am having trouble having 0 loop at the beginning if i type in 01234
it will just output -1-22-333-4444 but when i type in 1023 it will show 1-0-22-333 correctly. ive been trying to create a statement that would make 0 = 1 then output using cout <<"0"; i believe the problem is in if (b == count)

note: i am a beginner and

here is my program

#include <iostream>
#include <cmath>

using namespace std;
int main ()
{
	int num; 
	char choice;
	
	do {
		int count = 0, remain, quotient;
		
		cout << "\nEnter an integer value: ";
		cin >> num;
		
		if (num <= 0 || num >= 2147483647) // maximum storage memory for int
			cout << "\nInvalid number!\n";
		else {
			for (int a = num; a != 0; ++count) { // counts number of digits 
				a /= 10;
			}
			for (int b = count; b > 0; b--) { // isolates each digit
				quotient = num / (int) pow(10, b - 1);
				remain = num % (int) pow(10, b - 1);
				if (b == count)
					cout << "";
				else 
					cout << "-";	
				if (quotient == 0)
				cout << "0";		
					
				for (int c = quotient; c > 0; c--) { // repeats digits according to their value
					cout << quotient;
					
					
					num = remain;
				}
			}
			cout << "\n\nEnter <y>es to continue or <n>o to discontinue: ";
			cin >> choice;
		}
	} while (choice == 'y' || choice == 0);
	cout << "\nProgram ended\n";
}

[Ganado]

The number 012345 is stored as just an int. Its the same number as 12345 or 00000012345 (ignoring octal notation).
You would have to originally store the "number" as a string, to keep the leading zero info.

Quick example I made:

// Example program
#include <iostream>
#include <string>
#include <sstream>

int main()
{
  std::string num;
  std::cin >> num; // input the "number" as a string
  
  for (int i = 0; i < num.length(); i++)
  {
      // store character of the string into a
      // stringstream for later conversion
      std::stringstream ss;
      ss << num[i];
      
      // convert the character into an int:
      int n;
      if (ss >> n) // check success of conversion
      {
          // print the character out n times:
          for (int i = 0; i < n; i++)
          {
              std::cout << n;
          }
          std::cout << std::endl;
      }

  }
  
}

PS: Welcome to the forum=)

Also please read this for next time:
http://www.cplusplus.com/articles/jEywvCM9/

[machegache]

we are only allowed to use #cmath and #iostream but thank you anyways

[Too Explosive]

You could input it as a string then use a for loop and switch statement like so

for(int i = 0; i < number.length(); i++)
{
     switch(number[i])
     {
     case '0':
          cout << '0';
          break;
     case '1':
          cout << '1';
          break;
     case '2':
          cout << "22";
          break;
     case '3':
          cout << "333";
          break;
     case '4':
          cout << "4444";
          break;
     case '5':
          cout << "55555";
          break;
     case '6':
          cout << "666666";
          break;
     case '7':
          cout << "7777777";
          break;
     case '8':
          cout << "88888888";
          break;
     case '9':
          cout << "999999999";
     }
}

That should solve the problem and satisfy the constraints.

[E0p9LyTq]

You could input it as a string

The OP stated they can only use <cmath> and <iostream>, <string> is "off-limits."

One work-around could be a char array, use the null terminator for the loop comparison.

[Too Explosive]

Yes my apologies about the input. But yes try using a char array then use array.size() for the condition in the for loop.

[E0p9LyTq]

He can't use array.size(), that is a C++11 container construct he can't use. It would require he include the <array> header.

Create a C-string char array: char input[256];

Use std::cin.getline() to input the entire number as a C-string, including the null terminator '\0'

Then use the null terminator as the test condition in the for loop:
for(int i = 0; input[i] != '\0'; i++)

#include <iostream>

int main()
{
   std::cout << "Enter a number: ";
   char number[256];
   std::cin.getline(number, 256);
   
   for (int i = 0; number[i] != '\0'; i++)
   {
      switch (number[i])
      {
      case '0':
         std::cout << "0 ";
         break;
      
      case '1':
         std::cout << "1 ";
         break;
      
      case '2':
         std::cout << "22 ";
         break;
      
      case '3':
         std::cout << "333 ";
         break;

      case '4':
         std::cout << "4444 ";
         break;

      case '5':
         std::cout << "55555 ";
         break;

      case '6':
         std::cout << "666666 ";
         break;

      case '7':
         std::cout << "7777777 ";
         break;

      case '8':
         std::cout << "88888888 ";
         break;

      case '9':
         std::cout << "999999999 ";
      }
   }
   std::cout << "\n";
}

Enter a number: 01258
0 1 22 55555 88888888

I used nothing more than some core C++ keywords and the <iostream> library. No need for <cmath> at all.