write program with two nested for loops that produces the following.

[DesmondLee]

D3 D4 D5 D6 D7
E3 E4 E5 E6 E7
F3 F4 F5 F6 F7
G3 G4 G5 G6 G7

[48T7M4Gy]

#include <iostream>

int main()
{
    for(int i = 0; i < 1; i++)
    {
        std::cout
        << "D3 D4 D5 D6 D7\n"
        << "E3 E4 E5 E6 E7\n"
        << "F3 F4 F5 F6 F7\n"
        << "G3 G4 G5 G6 G7\n";
        for (int j = 0; j < 1; j++)
            std::cout << "Thankyou\n";
    }
    
    return 0;
}

[Boilerplate]

@DesmondLee - Although I prefer kemort's solution :) here's another to get you started:
Start with a string "DEFG". Loop through each element with another loop counting from 3 to 7.

[dhayden]

The outer loop prints lines. The inner loop prints items in the line:

    for (char letter = 'D'; letter <= 'G'; ++letter) {
        for (int number = 3; number <= 7; ++number) {
              ....
        }
    }

[DesmondLee]

okay Thanks for the reply @ kemort @Boilerplate @ dhyaden
i will try it out

[DesmondLee]

#include<iostream>
using namespace std;
int main()
{
	char letter;
	int number;

	for (letter = 'D'; letter <= 'G'; ++letter)
	{
        for (number = 3; number <= 7; ++number) 
		{
		cout<<letter;
		cout<<number;
        }
		cout<<endl;
	}
	system("Pause");
	return 0;
}

Thank you for the guidance. i did it.