array function, sum

[newguy17]

Write your question here.

good day, im having difficulty understanding the problem "cannot convert double to int for argument". sometimes when i change something and runs, it give a sum of 1. im new and and help would be appreciated.

  #include<iostream>

using namespace std;

void menu();
int add(int a[],int size);

int main()
{
	int operation;
	double num[4];
	
	menu();
	cout<<"Choose Operations: ";
	cin>>operation;
	
	if(operation==1){
		for(int x=0;x<4;x++){
			cout<<"Enter Value " <<x+1 <<": ";
			cin>>num[x];
			add(num,x);
		}
		cout<<"the Sum is: " <<add <<endl;
	}	
	
}

void menu(){
	
	cout<<"Operations" <<endl;
	cout<<"1 add" <<endl;
	cout<<"2 subraction" <<endl;
	cout<<"3 Multiplications" <<endl;
}

int add(int a[],int size){
	int sum=0;
	for(int x=0;x<size;x++)
	{
		sum=sum+a[x];
	}
	return sum;
	
}

[SECMoG1T]

your error is on line 11

///double num[4]; this
///should be
 int num[4];

[ne555]

or double add(double a[],int size)

[newguy17]

thank you for your reply. it runs but why im getting the answer 1 in my sum? thanks again

[SECMoG1T]

hello you aren't adding the values,

if(operation==1){
                int total =0;///create a variable
                int size = 4;

		for(int x=0;x<size;x++){
			cout<<"Enter Value " <<x+1 <<": ";
			cin>>num[x];
			///add(num,x); call the function outside the loop
		}
                total = add(num,size);
		cout<<"the Sum is: " <<total<<endl;
	}

[newguy17]

thank you all for the replies. god bless you all.