output digits of an n number

[Rale]

Hello guys,
I have an problem with outputting all digits of an number. I know with 2, 3, 4, 5, 6 and so but i need to write all this code for lets say 3 digits.

  int main()
{
    int a, b, c, d;
    a = 123;

    b = a % 10;
    a /= 10;
    
    c = a % 10;
    a /= 10;
    
    d = a % 10;

    cout << d << " " << c << " " << b << " ";

    return 0;
}

But can i somehow do this with a loop? And my question is what if n number was idk 123975234, how i can output all his digits with an loop, but not using 10000000 lines. Btw poor eng. Thanks :D :D :D

[jonnin]

how about

for(p10=10,i = 0; i < maxdigs; i++) //you can actually get max from a log call... log10(a)+1
{
cout << a% p10 << " ";
p10*=10;
}
cout << endl; //optional cleanup

[Rale]

Thanks, but that is too complicated to me, im beginner D:. Something simple?

[jonnin]

well its also apparently wrong... oops !


for(i = 0; i < maxdigs; i++) //you can actually get max from a log call... log10(a)+1
{
cout << a% p10 << " ";
a /= 10;
}
cout << endl; //optional cleanup

that should do better. The earlier version would write 3, 23, 123 for 123...
this one should correctly do 3, 2, 1

it does not get much more simple, but ask about what you do not understand.

[lastchance]

#include <iostream>
void digits( unsigned long long n ) { if (n) std::cout << ( digits(n/10), n%10 ) << "  "; }
int main() { digits( 123975234 ); }