String binary addition (Help)

A binary number is a base-2 number composed of the binary digits (bits) 0 and 1. For
example, the binary numbers 1, 10, 11, 111 are of decimal values 1, 2, 3, 7,
respectively. Addition of two binary digits follow the rules of 0+0=0, 0+1=1, 1+0=1 and
1+1=10. The sum of two binary numbers can then be obtained in the same way as
we add two decimal numbers, i.e., starting from the least significant place, we add the
corresponding digits of the two numbers and propagate any carry digit to the next,
more significant place. The following two figures illustrate the addition for decimal
numbers and for binary numbers. Note that the carry bit for binary addition can only In 1.cpp , write a C++ program that reads two strings, each representing a binary
number, supplied by the user. The input strings are therefore binary strings containing
a sequence of 0’s and 1’s. Your program should output the sum of the two binary
numbers. You may assume that the input numbers, if nonzero, always start with a 1 .
This is the same for the output sum, i.e., a nonzero sum should always start with a
1 . You should NOT make any assumption to the maximum length of the input
binary strings (i.e., the input strings can be as long as what a string object in C++
can be.)

Test cases
1_1
10101010
11001100
101110110

1_2
11111
1
100000

1_3
0
0
0

1_4
10001
11
10100

1_5
110001110001001010100111011101100101001011010111
10111000100110001010001000110110010111000001111
1001000110101111011111000100100011000000011100110

I have no idea how can i do it!Please give me a hand.
Consider:
1234
12

The answer is 1246, not 2434 as you are doing above. In decimal, you add units, tens, hundreds, ... together and not mix them, and have to use carry to cross these boundaries. The same goes for binary.

So, 4 is:
10001 + 00011, not 10001 + 11000.
@kbw
How can I do it?

I still don't know how to write the program!
You do it the same way as you do decimal.
I've been trying to post an example, but can't get the formatting right.
Last edited on
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