It only outputs to 2 digits! So, in the example below, it outputs 2.25. Not sure what's going on. I'm sure it's something silly...
If anyone knows and cares to share, it's much appreciated. Any other criticism or advice gratefully accepted.
Assignment specs:
Given a positive real number n, and an approximation for its square root, approx, a closer approximation to the actual square root, newapprox, can be obtained using the formula:
Using this information, write a program that prompts the user for a positive number and an initial approximation to the square root of the number, and then approximates the actual square root of the number accurate to 0.00001.
Hint: Using the initial approximation as the first value of approx, repeatedly calculate a newapprox, using the above formula, until the absolute value of the difference between the newapprox and approx is less than or equal to 0.00001. If the difference is greater than 0.00001, then calculate another newapprox, using its previous value as the value of approx.
Note: The function fabs should be used to calculate the needed absolute value. To find the absolute value of a variable x, include this code: fabs(x) Note: To use this function, you need to add #include <cmath> after the other include statement at the beginning of your code.
A sample run:
Enter n: 5
Enter first approximation: 2
The square root of 5 = 2.23607
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#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;
double calcRoot (double, double);
int main(){
double x, approx, newApprox;
cout << "Enter n: ";
cin >> x;
x = fabs(x);
cout << "Enter first approximation: ";
cin >> approx;
while (approxnewApprox > 0.00001) {
newApprox = calcRoot (x, approx);
}
cout << newApprox;
return 0;
}
double calcRoot (double x, double approx){
double newApprox;
newApprox = ((x/approx) + approx)/2;
return newApprox;
}
 