Need help with a class assignment.

[EmmyScott]

I was assigned to make a console app that when debugged should ask for a month then ask for a year then it should determine whether it is a leap year or not. This is what I have at this point in time.

int year;
int monthNumber;

cout << "Please enter a month as an integer (Jan. = 1, Feb = 2, etc.): ";
cin >> monthNumber;
cout << "Please enter a year (4-digit integer): ";
cin >> year;

int remainder = year % 4;
switch (remainder) { 
    case 1: 
        break;

I also have to use the switch function to do so. I just can't figure out where to go from here. Any words of wisdom? In the end I am supposed to be able to enter "2" for February and then enter 2008, then it would put out 29 days for it is a leap year. Then if I were to enter "2" then enter 2009 it would output 28. Then just the regular 30-31 days for the rest of the months.

[Duthomhas]

Be careful how you word things. Your assignment appears to be:

    “Print the number of days in a month, given the month and year.”

I recommend you write yourself a couple of functions. The first is:

    bool is_leap_year( int year )

Determining whether or not a year is a leap year in the Revised Gregorian system is a well-known formula. See https://www.geeksforgeeks.org/program-check-given-year-leap-year/

The second function is:

    int days_in_month( int month, int year )

This function should tell you the number of days in a month given a year. It should use the first function to compute the answer for February.

BTW. You are not "debugging" an application when you "run" or "execute" it.

Hope this helps.

[EmmyScott]

Thanks BIG time. My terminology isn't on point yet lol. Almost halfway through the semester I don't know these things yet. When I learn em I'll think of you lmao! I also have been working on this through out the day and have gotten this so far if you wanna comment on this edit?

	int y;
	int m;

	cout << "Please enter a month as an integer (Jan. = 1, Feb. = 2, etc.): ";
	cin >> m;
	cout << "Please enter a year (4-digit integer): ";
	cin >> y;

	int remainder = m % 4;
	switch (remainder) { 
		case 1: 
			cout << "31 days" << endl;
			cin >> remainder;
			break;
		case 2:
			cout << "28 days" << endl;
			cin >> remainder;
			break;
		case 3:
			cout << "31 days" << endl;
			cin >> remainder;
			break;
		case 4:
			cout << "30 days" << endl;
			cin >> remainder;
			break;
		case 5:
			cout << "31 days" << endl;
			cin >> remainder;
			break;
		case 6:
			cout << "30 days" << endl;
			cin >> remainder;
			break;
		case 7:
			cout << "31 days" << endl;
			cin >> remainder;
			break;
		case 8:
			cout << "31 days" << endl;
			cin >> remainder;
			break;
		case 9:
			cout << "30 days" << endl;
			cin >> remainder;
			break;
		case 10:
			cout << "31 days" << endl;
			cin >> remainder;
			break;
		case 11:
			cout << "30 days" << endl;
			cin >> remainder;
			break;
		case 12:
			cout << "31 days" << endl;
			cin >> remainder;
			break;

[Duthomhas]

Remember, computers cannot look ahead to see how things work. They only understand things one step at a time.

What is "remainder" here?

What is the range of values you can get when computing the remainder of division by 4?

What is the consequence of starting with January == 1?

There is a pattern here that has two twists:

Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
31  2?  31  30  31  30  31  31  30  31  30  31
    ↑                       ↑
    February is weird       The pattern skips at August

You can write a very small function that handles this weirdness very easily:

    month 2 (February) is 28 + is leap year
    months 1..7 are 30 days + is odd
    months 8..12 are 30 days + is even

You do not need to input (cin) anything after your initial inputs for month and year.

[EmmyScott]

int main() 
{

	int year;
	int month;

	cout << "Please enter a month as an integer (Jan. = 1, Feb. = 2, etc.): ";
	cin >> month;
	cout << "Please enter a year (4-digit integer): ";
	cin >> year;

	int remainder = month % 4;
	switch (month) {
			// 31 days.
		case 1:
		case 3:
		case 5:
		case 7:
		case 8:
		case 10:
		case 12: 
			cout << "31 days" << endl;
				break;
			// 30 days.
		case 4:
		case 6:
		case 9:
		case 11: 
			cout << "30 days" << endl;
				break;
			// February is special.
		case 2: 
			cout << "28 days" << endl;
				break;
			// Invalid value for month!
		default:
			cout << "29 days" << endl;
				break;
		}
	system("pause");
	return 0;

A lot of thing are of me using other people's work as a guide. Then my unknowing self I guess just tries to mesh it all together lol. I've got a little help from a class mate. This is the new and ?improved?

(disclaimer) I kinda just threw the 29 in down there cause I was trying to do some tinkering and it doesn't work the way I thought.