Trying to add the three constants

[bored622]

So the assignment requires us to make a game of Craps and also put three constants in the program. The game works I'm just trying to figure out how I would get a constant into the code. I have set three constants. SnakeEyes = 2, Boxcars = 12, and BigRed =7. Should I be going at this another way?

  #include <iostream>
#include <ctime>
#include <time.h>
#include <cstdlib>

using namespace std;

int main()
{
	int die1; //The first die.
	int die2; //The second die.
	int rollingDice; //When the player throws dice
	int rollingDice2 = 0; //When the player throws the dice if the first throw didn't give a winning or losing outcome.
	const int SnakeEyes = 2; //If the player throws two ones.
	const int BoxCars = 12; //If the player throws two sixes.
	const int BigRed = 7; //If the player throws a three and four

	srand(22);

	die1 = rand() % 6 + 1; //Simulates a six sided die
	die2 = rand() % 6 + 1;
	rollingDice = die1 + die2; //Adds the dice together.



	cout << "Player rolled: " << die1 << " + " << die2 << " = " << rollingDice << endl << endl; //Shows what the player rolled on first try.

	if (rollingDice == 7 || rollingDice == 11) //Player wins if they get a 7 or 11.
        {
            cout << "You won!" << endl;
            cin.get();
            return 0;
        }

	if (rollingDice == 2 || rollingDice == 3 || rollingDice == 12) //Player loses if they get a 2, 3, or 12 on first try.
        {
            cout << "Craps! You lost!" << endl;
            cin.get();
            return 0;
        }


	else
        {
            cout << "The Point is " << rollingDice << endl << endl; //If the player rolled a 4, 5, 6, 8, 9, or 10 on first try the game continues.
        }

        if (rollingDice == BoxCars)
    {
        cout << "Boxcars!" << endl;
    }

	while (rollingDice2 != rollingDice && rollingDice2 != 7) //Attempts will be made until the player either rolls the same number or a 7.
        {

            die1 = rand() % 6 + 1;
            die2 = rand() % 6 + 1;
            rollingDice2 = die1 + die2;

            cout << "Player rolled: " << die1 << " + " << die2 << " = " << rollingDice2 << endl << endl;



                if (rollingDice2 == rollingDice)
                    {
                        cout << "You rolled your point! You won!" << endl; // The player matched their number they won.
                    }

                if (rollingDice2 == 7)
                    {
                        cout << "You seven'd out and lost!" << endl; // The player got a total of seven they lost.
                    }

        }

	cin.get();
	return 0;

}

[keskiverto]

I'm not sure what you ask.

However a note, you have essentially:

	const int BoxCars = 12; //If the player throws two sixes.
	rollingDice = die1 + die2; //Adds the dice together.
	if ( rollingDice == 12)
        {
            return 0;
        }

        if (rollingDice == BoxCars)
       {
           cout << "Boxcars!" << endl;
       }

IF you roll 12 THEN the game ends immediately
that is ok, but right after you test whether you did roll 12
That can never be true.