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Merge two codes into one

Nookie (2)
Hello. I'm new here. I'm learning in Dev-C++ and so far i made a simple console. It's about sorting small and big coins.
Now i finish the code, and i wanna to improve it. Was searching for answer and come close to what i need, but i face
with a problem when i try to merge the 2 codes that i wrote.
The first code is to sort how many small or big coins are inserted in the deposit.
The second code is a program that will only tell me when i have put more than 4 coins and so on...(4, 5, 6...)
- Small coins: 1, 3, 5.
- Big coins: 10, 20, 30.

Example for the first code:
- I enter the following numbers:
1-1-5-3-3-5-20-1-30-10-20-10-10-30

Now the first code is for the value of coins and it runs like this:
Please Enter The Value Of Coins: 1
Small Coins Counted: 1
Please Enter The Value Of Coins: 1
Small Coins Counted: 2
Please Enter The Value Of Coins: 5
Small Coins Counted: 3
Please Enter The Value Of Coins: 3
Small Coins Counted: 4
Please Enter The Value Of Coins: 3
Small Coins Counted: 5
Please Enter The Value Of Coins: 5
Small Coins Counted: 6
Please Enter The Value Of Coins: 20
Big Coins Counted: 1
Please Enter The Value Of Coins: 1
Small Coins Counted: 1
Please Enter The Value Of Coins: 30
Big Coins Counted: 1
Please Enter The Value Of Coins: 10
Big Coins Counted: 2
Please Enter The Value Of Coins: 20
Big Coins Counted: 3
Please Enter The Value Of Coins: 10
Big Coins Counted: 4
Please Enter The Value Of Coins: 10
Big Coins Counted: 5
Please Enter The Value Of Coins: 30
Big Coins Counted: 6

Example for the second code:
- I enter the following amount of coins:
2-1-1-2-1-3
The second code is to count how many coins i insert
and it will print after i insert 4 or more amount of coins:

Number Of Insert Coins: 2
Insert Next Number of inserted coins: 1
Insert Next Number of inserted coins: 1 (<- this is where i reach 4 coins)
Total Number of coins inserted is: 4
Type The Next Number Of Coins Inserted : 1
Total Number of coins inserted is: 5
Type The Next Number Of Coins Inserted : 1
Total Number of coins inserted is: 6
Type The Next Number Of Coins Inserted : 2
Total Number of coins inserted is: 8
Type The Next Number Of Coins Inserted : 1
Total Number of coins inserted is: 9
Type The Next Number Of Coins Inserted : 3
Total Number of coins inserted is: 12

Now this is my problem trying to merge this 2 codes together and make the output look like this:

Using the same numbers:
1-1-5-3-3-5-20-1-30-10-20-10-10-30

Console output:
Please Enter The Value Of Coins: 1
Please Enter The Value Of Coins: 1
Please Enter The Value Of Coins: 5
Please Enter The Value Of Coins: 3
Small Coins Counted: 4
Please Enter The Value Of Coins: 3
Small Coins Counted: 5
Please Enter The Value Of Coins: 5
Small Coins Counted: 6
Please Enter The Value Of Coins: 20
Please Enter The Value Of Coins: 1
Please Enter The Value Of Coins: 30
Please Enter The Value Of Coins: 10
Please Enter The Value Of Coins: 20
Please Enter The Value Of Coins: 10
Big Coins Counted: 4
Please Enter The Value Of Coins: 10
Big Coins Counted: 5
Please Enter The Value Of Coins: 30
Big Coins Counted: 6

Can some one help me to merge this 2 codes together?
Thank you very much, and i appreciate your attention. 


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//This is the first code

#include <iostream>
using namespace std;
int main(int argc, char argv) 
{
	bool misss1b2 = false;
	int s1b2 = 0;
	for(;;)
	{
	int a;
	cout << endl << "Please Enter The Value Of Coins: ";
	cin >> a;
	if(a == 1 || a == 3 || a == 5 )
	{
		if(misss1b2 == false)
		{
			s1b2=1;
			misss1b2 = true;
		}
		else
		{
			s1b2++;
		}
		cout << endl << "Small Coins Counted: " << s1b2 << endl;
	}
	else
	{
		if(a == 10 || a == 20 || a == 30)
		{
			if(misss1b2 == true)
			{
				misss1b2 = false;
				s1b2 = 1;
			}
			else
				s1b2 ++;
				cout << endl << "Big Coins Counted: " << s1b2 << endl;
			}
	}
}
	return 0;
}
 
// This is the second code
#include <iostream>
using namespace std;

int main() 
{
	int coins = 1;
	int coins2 = 3;
	int a;
	int b = 1;
	int c;
	
	cout << " Number Of Insert Coins: " ;
	for (;;)
	{
	if (coins < 4)
	{
		while(coins < 4)
		{
			cin >> a;
			cout << " Insert Next Number of inserted coins: ";
			coins = coins + a;
			b = b + 1;
		}
	}
	else (coins2 > 4 || coins2 == 4);
	{
//If the number of coins inserted is greater than 10 than the program will print how much coins where inserted in the safebank
		cin >> a;
		coins2 = coins2 + a;
		cout << endl << "Total Number of coins inserted is: " << coins2 << endl;
		cout << endl << " Type The Next Number Of Coins Inserted : ";
	}			
	}
	
	return 0;
}
coder777 (8439)
Now this is my problem trying to merge this 2 codes together and make the output look like this:
Actually it shows only the output of the first code.

Otherwise you could turn the two main() into two function with other names and call them from third main():
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void first_code()
{
	bool misss1b2 = false;
	int s1b2 = 0;
	for(;;)
	{
	int a;
	cout << endl << "Please Enter The Value Of Coins: ";
	cin >> a;
	if(a == 1 || a == 3 || a == 5 )
	{
		if(misss1b2 == false)
		{
			s1b2=1;
			misss1b2 = true;
		}
		else
		{
			s1b2++;
		}
		cout << endl << "Small Coins Counted: " << s1b2 << endl;
	}
	else
	{
		if(a == 10 || a == 20 || a == 30)
		{
			if(misss1b2 == true)
			{
				misss1b2 = false;
				s1b2 = 1;
			}
			else
				s1b2 ++;
				cout << endl << "Big Coins Counted: " << s1b2 << endl;
			}
	}
}
}

void second_code()
{
...
}

int main() 
{
  first_code();
  second_code();
  return 0;
}
Nookie (2)
Thank you very much sir for helping me out.
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