my rand() works only if i use a cout

[MrNewbie]

Hi,
i'm doing a function to "flip a coin" and every time i try to start the program it works fine only if the code has a casual cout.
I'm using visual studio.

  #include <iostream>
using std::cout;
using std::cin;
using std::endl;

#include <cstdlib>
using std::rand;
using std::srand;

#include <ctime>
using std::time;

int flip();

int main()
{
    int testa = 0;//0
    int croce = 0;//1
    for (int i = 0; i < 100000; i++)
    {
        if (flip()== 0)
            testa++;
        else
            croce++;
    }
    cout << "Testa: " << testa << endl << "Croce: " << croce << endl;
    return 0;
}

int flip()
{
    int porcodio;
    srand(time(0));
    porcodio = rand() % 2;
    //cout << "porcodio" << endl; //here if i use this cout the function 
                                  //works 
    return porcodio;
}

my output without cout:
Testa: 100000
Croce: 0

my output with cout:
porcodio
porcodio
porcodio
...
Testa: 58010
Croce: 41990

[Ganado]

Printing just slows down your program enough such that it takes multiple seconds to complete, giving different srand seeds.

Move the srand call to be BEFORE your for loop.

PS: Cool it with the blasphemous remarks!

[MrNewbie]

Thanks now it works I hadn't really considered the time(0);